The area of a rectangle is calculated through the equation, V = L x W. That of the circle is equal to V = πr². These areas should be equal,
V = L x W = πr²
Substituting the known values,
2 ft x 11 ft = (22/7)(r²)
The value of r is sqrt 7.
Answer:
(a) (x-2)^2 +(y-2)^2 = 16
(b) r = 2
Step-by-step explanation:
(a) When the circle is offset from the origin, the equation for the radius gets messy. In general, it will be the root of a quadratic equation in sine and cosine, not easily simplified. The Cartesian equation is easier to write.
Circle centered at (h, k) with radius r:
(x -h)^2 +(y -k)^2 = r^2
The given circle is ...
(x -2)^2 +(y -2)^2 = 16
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(b) When the circle is centered at the origin, the radius is a constant. The desired circle is most easily written in polar coordinates:
r = 2
Answer:
About 5.5, but it is technically closer to 5.6 so I am not entirely sure
Step-by-step explanation:
Since EB and DC are parallel, triangles ABE and ACD are similar by AA. Therefore:
Hope this helps!
-10= ( -4)+(-3)+(-2)+(-1)
Answer:
The third one
Step-by-step explanation:
Its asking if its positive in the interval [-3, -2]
Which means you only look at the graph from -3, -2 on the x axis and we are looking see which one is positive in that space. And by positive it means going up in a positive direction. Only the third one does this.
