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stira [4]
3 years ago
14

In a lottery​ game, a single ball is drawn at random from a container that contains 25 identical balls numbered from 1 through 2

5. find the probability that the number drawn is even or a multiple of 6.
Mathematics
1 answer:
Semmy [17]3 years ago
5 0

There are 12 even numbers in the container.

Prob(drawing an even number) = 12/25

All multiples of 6 are even so the answer is 12/25.

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Evaluate 13+ab,when a= 2.5 and b=3.
Doss [256]

Answer:

the answer is 20.5 (B)

Step-by-step explanation:

13+2.5*3

<em>=20.5</em>

6 0
3 years ago
Read 2 more answers
On a recent quiz, the class mean was 72 with a standard deviation of 4.2. Calculate the z-score (to 2 decimal places) for a pers
barxatty [35]

Answer:

The Z score of the person is -3.09.

Step-by-step explanation:

The standard normal deviate (Z) for a normal distribution is given by

Z=\frac{X-\bar{X}}{\sigma }

where,

X = the value of observation

\bar{X} is mean of the observations and

σ = standard deviation of the score

Applying values we get

Z=\frac{59-72}{4.2}=-3.09

5 0
4 years ago
SOMEONE HELP! i dont understand this
Andrei [34K]

Answer:

14/50 or 7/25 or 0.28 or 28%

Step-by-step explanation:

The spinner is spun 50 times.  (8+6+9+11+9+7=50)

It lands on 1 or 2 a total of 14 times. (8+6=14)

So the experimental probability is 14 out of 50.  There are several ways this can be represented.  It depends on what your teacher wants.  it could be as a fraction or a decimal or a percentage.

14/50 or 7/25 or 0.28 or 28%

4 0
4 years ago
It has been hypothesized that the standard deviation of the germination time of radish seeds is 8 days. The standard deviation o
Yanka [14]

Answer:

\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

p_v =2*P(\chi^2 >33.19)=0.0053

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

Step-by-step explanation:

Data given

n=60 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =6^2 =36 represent the sample variance obtained

\sigma^2_0 =8^=64 represent the value that we want to test

Hypothesis to test

We want to verify if the true deviation is equal to 8 days o not, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 64

Alternative hypothesis: \sigma^2 \neq 64

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

Replacing we got:

\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

p_v =2*P(\chi^2 >33.19)=0.0053

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

6 0
4 years ago
What is the solution of the system of equations shown in the graph below?
Wittaler [7]

Answer:

The point on the plane (4, 2)

That is x = 4 and y = 2

Step-by-step explanation:

Look for the point where the two lines given by the system of linear equations  intersect. That point is (4, 2)

x = 4 and y = 2

6 0
3 years ago
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