1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slavikrds [6]
2 years ago
7

Anyone know the answers for either one?

Mathematics
2 answers:
anastassius [24]2 years ago
8 0
I’m not sure I am so sorryyyyyyyyyyyyyy
Neporo4naja [7]2 years ago
7 0

Answer:

nah

Step-by-step explanation:

but search up a tutorial that helps me

You might be interested in
A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq
Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

3 0
3 years ago
Find the domain and range of the following function ƒ(x) = 5|x - 2| + 4
Inessa [10]

Answer:

this is the answer fod this lroblsm

6 0
3 years ago
What is the probability of rolling an even number when rolling a 6-sided die?
lukranit [14]

Answer:

B.1/2

Step-by-step explanation:

Half of the numbers on a dice are even, so you have a 1 half probability of landing on an even number

7 0
3 years ago
Evaluate x + y + z if x = 3, y = -5, and z = -2
Eduardwww [97]

x + y + z

  • Substitute the given values for x, y, and z.

(3) + (-5) + (-2)

  • Rewrite the equation.

3 - 5 - 2

  • Solve from left to right.

3 - 5 = -2

-2 - 2 = -4

<h3>Your answer is -4.</h3>
7 0
3 years ago
Simplify 4a^3 b^2 x 6a^6b^9
Ket [755]

Answer:

24a^9 b^11

Step-by-step explanation:

4a ^{3} b ^{2}  \times 6a ^{6} b ^{9}  \\  = (4 \times 6)a ^{3 + 6}b ^{2 + 9}  \\  = 24a^{9} b^{11}

5 0
3 years ago
Other questions:
  • A zoo kitchen's weekly grocery list shows the zoo orders 56pounds of each week . The zoo kitchen is the same number of pounds of
    9·1 answer
  • Answer this pleaseeee
    12·1 answer
  • Penny reads 10 pages in 1/4 hour.what is the unit rate for pages per hour?For pages per page? The unit rate is blank hour(s) per
    6·1 answer
  • Terrance has 95 tickets saved up from the last time he went to the arcade. He is planning a trip to the arcade this weekend and
    12·1 answer
  • What is the value of x?<br><br><br><br>_______. degrees
    14·1 answer
  • Michelle opened her bank account on September 1st with $25 and continues to deposit $25 each month.
    13·1 answer
  • Please help, thanks if you do :)
    8·1 answer
  • Complete the explanation on how you can use base-ten blocks to find 1.59 + 2.18. First
    6·1 answer
  • - 3 7/9 - 1 2/9 <br> What is this answer
    11·2 answers
  • B) A group of middle schoolers has 8 boys and 24 girls. What is the
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!