Question

Find the perimeter of a rectangle is 56 cm. the length of the rectangle is 2 cm more than the width

Answer 1

P = 56 = 2l + 2w and l=2+w

56 = 2(2+w)+2w
56 = 4 + 2w + 2w
52 = 4w
w = 13 cm
l = 13+2
l = 15 cm

Answer 2

We call :  → l = lenght
                                                                       We know the perimeter of the 
                    w = width                                      the rectangle : P = 2(w+l)

                    P = perimeter


P = 2(w+l)          but l = w+2

56 = 2(w+w+2)

56 = 2(2w+2)

56 = 4w + 4

4w = 56 - 4

4w = 52                            l = w + 2

w = 52 : 4                         l = 13 + 2

w = 13 cm                        l = 15 cm