H = –16t2 + 156t + 105, when t = t', the time where the rocket hit the ground after it is launched, so 105= –16t'2 + 156t' + 105, so -16t'2 + 156t' = 0 implies t' =0 or -16t'+ 156= 0, equivalent to t'=9.75, so the answer is
b) <span>9.8 s</span>
Answer:
It has to be 16in since 256 is obviously to much and 4 and 8 are too little
Step-by-step explanation:
Answer:
Here it is. The table is on the first one at the bottom.
Step-by-step explanation:
Answer:
x = 30
Step-by-step explanation:
-2x + 10 +4x=70
-10 -10
-2x + 4x = 60
2x = 60
/2 /2
x = 30
Answer:
x = 26
Step-by-step explanation:
The sum of the angles around point O = 360°, thus
x + 3x + 256 = 360 , that is
4x + 256 = 360 ( subtract 256 from both sides )
4x = 104 ( divide both sides by 4 )
x = 26
