Answer: B
Step by step explanation: it’s less then 3/8 so it’ll be unlikely but not completely impossible
Answer:
±3/5
Step-by-step explanation:
±sqrt(9/25)
We can separate this into
± sqrt(9) / sqrt(25)
Since these are perfect squares
±3/5
Answer:
122
Step-by-step explanation:
An arithmetic sequence means a number is added each term. There is a term for where a number is multiplied as well. But in this case the first number is -103, the second number is -94 and the third number is -85. Can you tell what number is added each time?
The number is 9. -103+9=-94 and -94+9=-85 and so on. Now we want a way to find the term way further down the line.
Think of it doing it all at once. -103+9+9 gets us the third term right? so that's 2*9. -103+3*9 would get us the fourth. Hopefully that makes sense, but let me know if it doesn't. But for a few more examples, if we want the fifth term we would do -103+4*9 and getting the tenth would need -103+9*9. So basically we take the number term we want (in this case we want the 26th) and then take -103+ n*9, where n is the term we want minus 1, or in this case 25. so that's -103+25*9
Let me know if you need more of an explanation.
Answer:
1000
Step-by-step explanation:
2×500=1000
hope it helps
Note that while the figure is made up of rectangle and parallelogram, then the area of this figure
![A_{figure}=A_{rectangle}+A_{parallelogram}.](https://tex.z-dn.net/?f=A_%7Bfigure%7D%3DA_%7Brectangle%7D%2BA_%7Bparallelogram%7D.)
1. The area of rectangle is
![A_{rectangle\ ABCF}=AB\cdot BC.](https://tex.z-dn.net/?f=A_%7Brectangle%5C%20ABCF%7D%3DAB%5Ccdot%20BC.)
The vertices of rectangle are points A(-2,-2), B(0,-6), C(8,-2) and F(6,2). Then
![AB=\sqrt{(-2-0)^2+(-2+6)^2}=\sqrt{4+16}=\sqrt{20}=2\sqrt{5},\\ \\BC=\sqrt{(8-0)^2+(-2+6)^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}.](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%28-2-0%29%5E2%2B%28-2%2B6%29%5E2%7D%3D%5Csqrt%7B4%2B16%7D%3D%5Csqrt%7B20%7D%3D2%5Csqrt%7B5%7D%2C%5C%5C%20%5C%5CBC%3D%5Csqrt%7B%288-0%29%5E2%2B%28-2%2B6%29%5E2%7D%3D%5Csqrt%7B64%2B16%7D%3D%5Csqrt%7B80%7D%3D4%5Csqrt%7B5%7D.)
Therefore,
![A_{rectangle\ ABCF}=2\sqrt{5}\cdot 4\sqrt{5}=8\cdot 5=40\ un.^2](https://tex.z-dn.net/?f=A_%7Brectangle%5C%20ABCF%7D%3D2%5Csqrt%7B5%7D%5Ccdot%204%5Csqrt%7B5%7D%3D8%5Ccdot%205%3D40%5C%20un.%5E2)
2. The area of parallelogram can be calculated using formula
![A_{parallelogram\ FCDE}=\text{base}\cdot \text{height}.](https://tex.z-dn.net/?f=A_%7Bparallelogram%5C%20FCDE%7D%3D%5Ctext%7Bbase%7D%5Ccdot%20%5Ctext%7Bheight%7D.)
The base of parallelogram is segment CD with length
and the height has length 2 un. Then
![A_{parallelogram\ FCDE}=5\cdot 2=10\ un^2.](https://tex.z-dn.net/?f=A_%7Bparallelogram%5C%20FCDE%7D%3D5%5Ccdot%202%3D10%5C%20un%5E2.)
3. Now
![A_{figure}=40+10=50\ un.^2](https://tex.z-dn.net/?f=A_%7Bfigure%7D%3D40%2B10%3D50%5C%20un.%5E2)