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morpeh [17]
3 years ago
7

A city employee collected survey data from 2330 randomly selected residents. A total of 865 of these residents said that they th

ought the city should devote more city funds to repair roads.
To the nearest percent, what is a good estimate of the percentage of all residents who thought this?

Enter your answer in the box.
Mathematics
2 answers:
timurjin [86]3 years ago
5 0
About 37% because 865/2330 is .3712446352.  To find the percent, you move the decimal right two spaces. In your case, you would round to the nearest whole, which is 37%.
Rasek [7]3 years ago
3 0
Total residents = 2330

Resident who thought it = 865
% of residents who thought it = 865/2330 * 100 = 37.12%≈ 37%

Thus 37.12% of the resident thought it.
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Answerrr now. Plsss<br> :)
Lesechka [4]

Answer:

Alternate exterior

Step-by-step explanation:

They are on opposite sides and both exterior

4 0
3 years ago
Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv
Leona [35]

The inequality is used to solve how many hours of television Julia can still watch this week is x + 1.5 \leq 5

The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours

<h3><u>Solution:</u></h3>

Given that Julia is allowed to watch no more than 5 hours of television a week

So far this week, she has watched 1.5 hours

To find: number of hours Julia can still watch this week

<em>Let "x" be the number of hours Julia can still watch television this week</em>

"no more than 5" means less than or equal to 5 ( ≤  5 )

Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours

number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch

x + 1.5 \leq5

Thus the above inequality is used to solve how many hours of television Julia can still watch this week.

Solving the inequality,

x + 1.5 \leq5\\\\x \leq 5 - 1.5\\\\x \leq 3.5

Thus Julia still can watch Television for 3.5 hours

5 0
2 years ago
The question is above in the picture​
anzhelika [568]
Yea his answer is right ^^
6 0
3 years ago
Solve this x²+8/10 -x = 10/2
AysviL [449]
x^2+\frac{8}{10}-x=\frac{10}{2}\\&#10;x^2-x+\frac{8}{10}-\frac{10}{2}=0\\&#10;x^2-x+\frac{8}{10}-\frac{50}{10}=0\\&#10;x^2-x-\frac{42}{10}=0\\&#10;x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\&#10;(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\&#10;(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\&#10;(x-\frac{1}{2})^2=\frac{89}{20}\\&#10;x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\&#10;x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\&#10;&#10;&#10;
x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\&#10;x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\&#10;x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\
7 0
3 years ago
EXTRA POINTS!!! Write a system of three inequalities that has (2, 1) in the solution set.
Alex17521 [72]
Your system could be anything, just remember that input should be half than the output.

So, y ≥ 1/2x
5y ≥ 5/2x
10y ≥ 5x

Hope this helps!
5 0
3 years ago
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