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gavmur [86]
2 years ago
5

Three dressers are placed side by side. One dresser is 5 feet 9 inches wide, another is 3 feet 7 inches wide, and the third is 4

feet 10 inches wide. How wide are they combined? Write your answer in feet and inches. Use a number less than 12 for inches.
Mathematics
1 answer:
oksian1 [2.3K]2 years ago
3 0
(5*12+9)+(3*12+7)+(4*12+10)=170ft

170/12=14ft+2in

14' 2"
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Rita earns $10 per hour. She puts 5% of her earnings in savings. Write inequality to find how many hours Rita must work to save
Rina8888 [55]

Answer:

Rita must work 50 days  to save at least $25.

Step-by-step explanation:

The amount Rita earns per hour  = $10

The saving percentage =  5%

So, the savings of Rita per hour =  5% of $10

⇒5% of $10  = \frac{5}{100}  \times 10  = 0.5

or Rita saves $0.5 per hour.

The amount she wants to save at minimum  = $25

So, let she works at the minimum of k Days.

⇒\textrm{The number of hours she has to work}  = \frac{\textrm{Amount she needs saving}}{\textrm{Amount saved in 1 hour}}

or, k = \frac{25}{0.5}  = 50

The number of hours she has to work  =  50 days

Hence,  Rita must work 50 days  to save at least $25.

3 0
2 years ago
14. Write the equation in slope-intercept form that passes through the two points.
nordsb [41]

Answer: y=5x+7

Step-by-step explanation:

If you draw a graph or use a graphing calculator the points and then connect them you will see that the y-intercept is 7 and the slope is 5/1. Slope intercpt  form is y=mx+b. So the equation is y=5x+7.

8 0
3 years ago
Read 2 more answers
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
Show That The Points(-1, -3), (-4, 7), (2,-13) Are Collinear!!!
GaryK [48]

Answer:

3 Quadrant

2 Quadrant

4 Quadrant

They are Collinear.

Please Mark As Brain list

6 0
2 years ago
Read 2 more answers
Evaluate the integral. (Assume a ≠ b. Remember to use absolute values where appropriate. Use C for the constant of integration.)
Bess [88]

Answer:

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x + C.</em></u>

Step-by-step explanation:

<u><em>First step we aplicate distributive property to the function.</em></u>

<u><em>5*(x+a)*(x+b)= 5*[x^{2}+x*b+a*x+a*b]</em></u>

<u><em>5*[x^{2}+x*(b+a)+a*b]= f(x), where a, b are constant and a≠b</em></u>

<u><em>integrating we find ⇒∫f(x)*dx= F(x) + C, where C= integration´s constant</em></u>

<u><em>∫^5*[x^{2}+x*(a+b)+a*b]*dx, apply integral´s property</em></u>

<u><em>5*[∫x^{2}dx+∫(a*b)*x*dx + ∫a*b*dx], resolving the integrals </em></u>

<u><em>5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x</em></u>

<u><em>Finally we can write the function F(x)</em></u>

<u><em>F(x)= 5*[\frac{x^{3} }{3} + (a*b)*\frac{x^{2} }{2} + a*b*x ]+ C.</em></u>

4 0
3 years ago
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