All categories

3 years ago

Blain exchanges $100 for yen before going to Japan. If each U.S. dollar is worth 88.353 yen, how many yen should Blain receive?

Mathematics

2 answers:

Tcecarenko [31]3 years ago

5 0

To figure out how many yen all ya have to do is multiply 88.353 by 100 to get the answer 8835.3 yen.

Nina [5.8K]3 years ago

5 0

we know that

$1$ U.S. dollar is worth $88.353$ yen

by proportion

$\frac{1}{88.353}\frac{usd}{yen} =\frac{100}{x} \frac{usd}{yen} \\ \\ x=100*88.353\\ \\ x=8,835.3\ yen$

therefore

the answer is

$8,835.3\ yen$

You might be interested in

Solve for

NISA [10]

Answer:

The answer would therefore be 'x=18'.

7 0

2 years ago

Please help! will give brainliest

Juliette [100K]

Answer:

yes, the point (-1, 5) is in the solution set

Step-by-step explanation:

y ≥ 2x + 3

Is 5 ≥ 2(-1) + 3? Yes

y + x > 0

Is 5 + (-1) > 0? Yes

4 0

3 years ago

Read 2 more answers

Does anyone know how to do this help please

statuscvo [17]

Answer:

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

Put x = -3 :-

$\rm\implies y = 3^2-3-6\\$

$\rm\implies y = 9 - 3 - 6 \\$

$\rm\implies y = 0$

Put x = -2 :-

$\rm\implies y = 2^2-2-6\\$

$\rm\implies y = 4 -2-6\\$

$\rm\implies y = -4$

Put x = -1 :-

$\rm\implies y = -1^2-1-6\\$

$\rm\implies y = 1 -1-6 \\$

$\rm\implies y = -6$

Put x = 1 :-

$\rm\implies y = 1^2+1-6\\$

$\rm\implies y = 2 -6$

$\rm\implies y = -4$

Put x = 2 :-

$\rm\implies y = 2^2+2-6\\$

$\rm\implies y = 4 +2-6\\$

$\rm\implies y = 2$

Put x = 3 :-

$\rm\implies y = 3^2+3-6\\$

$\rm\implies y = 9 +3-6\\$

$\rm\implies y = 6$

Final table :-

$\boxed{\begin{array}{c|c|c|c|c|c|c|c} \bf x &\rm -3 &\rm -2 &\rm -1 &\rm 0 &\rm 1 &\rm 2 &\rm 3 \\\\ \bf y & \rm 0 &\rm -4 &\rm -6&\rm -6 &\rm -4&\rm 2 &\rm 6 \end{array}}$

7 0

2 years ago

PLEASE HELP ME!!!!!!!!!

vitfil [10]

$(x - 4) {}^{2} - 28 = 8 \\ (x - 4) {}^{2} = 8 + 28 \\ (x - 4) {}^{2} = 36$

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

$\sqrt{(x - 4) {}^{2} } = ± \sqrt{36} \\x - 4 = ±6 \\ x _{1}- 4 = 6 \: \: \: \: \: \: \: \: \: \: x _{2}- 4 = - 6 \\ x_{1} = 6 + 4 \: \: \: \: \: \: \: \: \: \: x_{2} = - 6 + 4 \\ x_{1} = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 2$

Well he started off correct to the point of completing the square.

$(x - 3) {}^{2} = 16 \\ x - 3 = ±4 \\ \: x_{1} - 3 = 4 \: \: \: \: \: \: \: \: \: \: \: \: x_{2} - 3 = - 4 \\ x_{1} = 7 \: \: \: \: \: \: \: \: \: \: x_{2} = - 1$

8 0

7 months ago

Which number satisfies the inequality 9h + 15 > 55?

telo118 [61]

9h + 15 > 55
- 15 - 15
9h > 40
h > 40/9
h > 4.44444.
any number greater than 4.44444

4 0

2 years ago

Read 2 more answers