Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer:
D ASA
Step-by-step explanation:
ASA
Answer:
p ∈ [5 , 6)
Step-by-step explanation:
p + 6 ≥ 11
⇒ p ≥ 11 - 6
⇒ p ≥ 5
⇒ p ∈ [5 , +∞)
3p < 18
⇒ p < 18/3
⇒ p < 6
⇒ p ∈ (-∞ , 6)
Then
p the solution to both equations verify:
p ∈ (-∞ , 6) ∩ [5 , +∞)
Conclusion :
p ∈ [5 , 6)
Answer:
Formula: 0.12x = y
Step-by-step explanation:
5 × 0.12 = 0.60
3 × 0.12 = 0.36
14 × 0.12 1.68
R=12.13
A=pi×r²
A=pi×12.13²
A≈462.2442041
A≈462.2 (to the nearest tenth).
So the answer is A≈462.2.