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Stella [2.4K]
3 years ago
13

Your second mortgage of $31,200 is at a rate of 10.7% compounded quarterly for 8 years. What total will you have paid for your s

econd mortgage after 8 years?
Mathematics
1 answer:
natulia [17]3 years ago
3 0

Answer:

The Amount paid after 8 years is $72611.76

Step-by-step explanation:

Given as :

The principal mortgage = p = $31,200

The rate of interest = r = 10.7%  compounded quarterly

The time period of mortgage = t = 8 years

Let The Amount paid after 8 years = $A

Now, According to question

<u>From Compounded Interest method </u>

Amount = Principal × (1+\dfrac{\textrm rate}{4\times 100})^{\textrm 4\times time}

Or, A = p × (1+\dfrac{\textrm r}{4\times 100})^{\textrm 4\times t}

Or, A = $31,200 × (1+\dfrac{\textrm 10.7}{4\times 100})^{\textrm 4\times 8}

Or, A = $31,200 × (1.02675)^{32}

Or, A = $31,200 × 2.3273

∴ A = $72611.76

So, The Amount paid after 8 years = A = $72611.76

Hence, The Amount paid after 8 years is $72611.76  Answer

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Step-by-step explanation:

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3 years ago
The mathematics department of a college has 6 male professors, 9 female professors, 5 male teaching assistants, and 6 female tea
Hitman42 [59]

Given:

6 male professores

9 female professores

5 male teaching assistants

6 female teaching assistants

Sol:.

N(A\text{ or B)=N(A)+N(B)-N(A and B)}

N (professors)

\begin{gathered} =6+9 \\ =15 \end{gathered}

N(Male)

\begin{gathered} =6+5 \\ =11 \end{gathered}

N(professors and male)

=6

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

\begin{gathered} N(\text{ Professors OR male)=15+11-6} \\ =20 \end{gathered}

N(People to choose from)

\begin{gathered} =6+9+5+6 \\ =26 \end{gathered}

Then probablitiy is:

\begin{gathered} =\frac{20}{26} \\ =\frac{10}{13} \end{gathered}

Then the probability is 10/13

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1 year ago
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Step-by-step explanation:

3 0
2 years ago
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Write an equation of the perpendicular bisector of the segment with end points M(1,5) and N(7,-1)
vitfil [10]
The perpendicular bisector of the segment passes through the midpoint of this segment. Thus, we will initially find the midpoint P:

P=\dfrac{(1,5)+(7,-1)}{2}=\dfrac{(8,4)}{2}=(4,2)

Now, we will calculate the slope of the segment support line (r). After this, we will use the fact that the perpendicular bisector (p) is perpendicular to r:

m_r=\dfrac{\Delta y}{\Delta x}=\dfrac{5-(-1)}{1-7}=\dfrac{6}{-6}\iff m_r=-1


p\perp r\Longrightarrow m_p\cdot m_r=-1\Longrightarrow m_p\cdot(-1)=-1\iff m_p=1

We can calculate the equation of p by using its slope and its point P:

y-y_P=m_p(x-x_P)\\\\&#10;y-2=1\cdot(x-4)\\\\&#10;y-2=x-4\\\\&#10;\boxed{p:~~y=x-2}
4 0
3 years ago
Suppose we roll a fair six-sided die 20 times and draw ten cards from a standard 52-card deck. Let X be the number of "6"s rolle
Lera25 [3.4K]

Answer:

a) Expected value = 6.406

Variance = 4.905

Standard deviation = 2.45

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Step-by-step explanation:

a) Let's suppose that:

X₁ = number of 6´s

X₂ = number of Jack, Queen, King or Aces

The mean of X₁ is:

MeanX₁ = n * p = 20 * (1/6) = 3.33

The variance of X₁ is:

Var-X_{1} =np(1-p)=3.33(1-(1/6))=2.775

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The expect value of X is:

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The variance of X is:

VarX = VarX₁ + VarX₂ = 2.775 + 2.13 = 4.905

The standard deviation is:

Xdevi = 4.905/2 = 2.45

b) The probability of drawing at least five six out of 20 rolls is equal to:

∑(1/6)ˣ(5/6)²⁰⁻ˣ = 0.231 with x = 5

The probability of at least 4 Jack, Queen, Kings or Aces is:

∑(16/52)ˣ(1-(16/52))¹⁰⁻ˣ = 0.37 with x = 4

The probability of given event is equal to:

P = 0.231 * 0.37 = 0.08547

5 0
3 years ago
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