Area of triangle = 1/2 × base × height
so,
24=1/2*base*4
base=12m
Where's the so-called "parabola tool?"
The vertex is relatively easy to find. Find the midpoint of the segment of the x-axis connecting x=2 and x=6; it is x=4. Then evaluate the function at x=4:
f(4) = (4-2)(4-6) = 2(-2) = -4. The vertex is at (4,-4).
Plot (4,-4). Then (arbitrarily) let x=0 and find y: f(0) = y = (-2)(-6) = -12.
So, when x = 0, y = -12.
Plot this point (1, -12). realize that the parabola is symmetric about the line x=4. (1,-12) is 3 units to the left of the axis of symm, and thus another point on the parab. is 3 units to the right of this axis, x= 7. Plot (7,-12). Now draw the parabola thru (7,-12), (1, -12) and (4, -4). The parab. opens up.
If estimating, round numbers to their nearest tens, $0.34 = 0.30, $0.22 = $0.20, $0.98 = $0.90. 30+20+90= 1.40
Either the second or third. I think the third since the second can be proven with the given info, and then you just need to know another angle from each triangle is congruent. also, its worth knowing that it is also possible to prove similar triangles with just angle angle, since that would automatically make the last angles equal.
answer is 10.69 add the two values together
