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Fed [463]
3 years ago
12

PLEASE I NEED THIS ASAP If you had a cell that was cube-shaped with a side length of 20µm, calculate the surface to volume ratio

of the cell. Round your answer to the tenths place.
Biology
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

Ratio = 3\times 10^5

Explanation:

Side of a cube, a = 20 µm

a=20\times 10^{-6}\ m

The surface area of a cube, A = 6a² (a is side of the cube)

The volume of a cube, V = a³

The ratio of the surface to volume ratio of the cell will be given by :

R=\dfrac{6a^2}{a^3}\\\\R=\dfrac{6}{a}\\\\R=\dfrac{6}{20\times 10^{-6}}\\\\R=3\times 10^5

So, the ratio of the surface to volume ratio of the cell 3\times 10^5.

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Blank layers of blank make up the cell membrane
sattari [20]

Answer:

Two layers of Lipids make up the cell membrane

Explanation:

The inner and outer phospholipid layers

3 0
1 year ago
3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
konstantin123 [22]

Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
  • Insolation energy is 800 calories/cm2/day
  • % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

8 0
3 years ago
If exhibited by an expectant father, what is a warning sign of ineffective adaptation to his partner's first pregnancy?
Sergio [31]

Answer:

Consistently changes the subject when the topic of the fetus/newborn is raised.

Explanation:

This is the decision of the couple whether they want a child or not and can discuss about the family planning as well. Different psychological aspects acn explain this matter.

The expectant father is not mentally prepared for the child. He might refuse the talks and stay away from the communication that are related to the new born child. This must be properly assessed and important to understand the feeling of the expectant father.  

Thus, the answer is consistently changes the subject when the topic of the fetus/newborn is raised.

4 0
3 years ago
Identify the two main regions of a typical mollusk's body
maria [59]
Head foot and visceral mass

Most of the mollusks species are gastropods. The body of the mollusk is made of shell and fleshy part. The fleshy part is divide into foot and visceral mass. Foot is a distinct feature of mollusk. They use it mainly for locomotion. The visceral mass involves the organs for circulation, digestion and other important processes in living organism. The visceral mass has two external flaps of tissue called as the mantle. It secretes calcerous shell and encloses a mantle cavity.
5 0
3 years ago
Read 2 more answers
Amoeba and paramecia are eukaryotic, single cellular, heterotrophic, and reproduces asexually. Into which kingdom would these or
Andreyy89

Answer: Option D.

Protist.

Explanation:

Amoeba and paramecia belong to kingdom protist.

This kingdom comprises of Eukaryotic organisms that are multicellular or unicellular. They have nucleus and membrane bound organelles which are use in performing life processes. Some protist are free living such as algae while some are heterotrophic and some are parasitic. They have Mitochondria and the live in moist or aquatic environment. They have cilia or flagella for loccomotion.

8 0
3 years ago
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