From point A to C, which is the length of the entire line, it's 3x + 1.
AB = 2x + 4
BC = 10
This means that AB + BC = AC
All you have to do is plug in the equations.
(2x + 4) + (10) = (3x + 1)
2x + 14 = 3x + 1
2x + 13 = 3x
13 = x
Now plug in the value of x (13) into the AC equation (3x + 1).
AC = 3(13) + 1
AC = 39 + 1
AC = 40
The answer is:
a. 40
To get which design would have maximum area we need to evaluate the area for Tyler's design. Given that the design is square, let the length= xft, width=(120-x)
thus:
area will be:
P(x)=x(120-x)
P(x)=120x-x²
For maximum area P'(x)=0
P'(x)=120-2x=0
thus
x=60 ft
thus for maximum area x=60 ft
thus the area will be:
Area=60×60=3600 ft²
Thus we conclude that Tyler's design is the largest. Thus:
the answer is:
<span>Tyler’s design would give the larger garden because the area would be 3,600 ft2. </span>
Answer:
-2
Step-by-step explanation:
given 2 points on a line (x1, yx) and (x2,y2)
the formula for slope, m = (y2-y1) / (x2-x1)
in this case,
x1 = 4, y1 = 3, x2 = 2, y2 = 7
Hence,
m = (7-3) / (2-4) = 4 / -2 = -2
Answer:
45.44/71 - 1 = -0.36 = -36%
36% decrease.
