Can somebody help me with this math question?
1 answer:
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Answer:
He needs 9 circular tables and 3 square tables.
Step-by-step explanation:
Given:
Number of persons in each circular table = 10
Number of persons in each square table = 4
Now, in order to maximize number of circular tables, we must find the maximum multiple of 10.
Multiples of 10 = 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.
Now, if we take 100, then the seats remaining are 2. But the square tables require 4 persons. So, 100 is not correct.
Next, if we choose 90 as a multiple of 10, then the circular tables used would be .
Now, number of guests left are 102 - 90 = 12. Now, 12 is a multiple of 4. So, 3 square tables can accommodate 12 persons as .
Therefore, he has to use 9 circular tables and 3 square tables to maximize the number of circular tables.