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Sindrei [870]
3 years ago
10

HELP, i don't understand this I put all my points pls help me with this

Mathematics
2 answers:
Nina [5.8K]3 years ago
6 0

Answer:

I cant see

Step-by-step explanation:

ollegr [7]3 years ago
6 0

Answer:

2+5*3+6*2+7*3+8*2 = 66

66/5 = 14

mean = 14

hope this helps

Step-by-step explanation:

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When a sunfloweris 2 weeks old it is 38 centimeters tall when it is 6 weeks old it is 114 cm tall how tall is it when it is 3 ½
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2 wk --- 38 cm
3.5 wk --- x cm
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What is the sum of the geometric sequence 1, 4, 16, ... if there are 8 terms?
mylen [45]

Answer:

1, 4, 16, 64, 256, 1024, 4096, 16384

Step-by-step explanation:

Multiply by 4

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You like to watch movies at the local theater. You have two payment options. Your first option is to buy a discount card which w
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The courtyard outside East Middle School is in the shape of a rectangle and half-circle.
Nadya [2.5K]

Answer:

The correct option is the third one counting from the top. (5892 m^2)

Step-by-step explanation:

First, we need to remember that:

For a rectangle of length L and width W, the area is:

A = L*W

For a circle of diameter D, the area is:

A = pi*(D/2)^2

Where pi = 3.14

In the image, we can see a rectangle and half a circle, the total area of the image will be equal to the area of the rectangle plus the area of the half circle.

In the image, we can see a rectangle of length L = 100m and width W = 50m

Then the area of the rectangle is:

A = 100m*50m = 5000m^2

And we can see that for the half-circle the diameter is D = 50m

Note that the area of a half-circle is half of the area of a complete circle, then the area of that half-circle is:

A = (1/2)*(3.14*(50m/2)^2) = 981.25 m^2

If we add these two areas we get:

Total area =  5000m^2 + 981.25 m^2 = 5981.25 m^2

If we round it up, we get:

Total area = 5982 m^2

The correct option is the third one counting from the top.

8 0
2 years ago
0.037 in scientific notation
Sedaia [141]

\huge\boxed{3.7\ \times\ 10^{-2}}

First, you need to find where you can move the decimal point to so that there is only one non-zero digit to the left of it.

Move the decimal point, and that is the first part done.

Add "\times\ 10".

For the last part - the power, you need to find how many decimal places you moved the decimal point. In this case, we moved it to the right 2 places, so the power is ^{-2}.

If, for example, we had moved the decimal point three places to the left, the power would be ^{3}.

7 0
2 years ago
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