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Gnoma [55]
3 years ago
10

A graph includes the ordered pair (2,4). Write two different rules that would be possible for this graph. Explain how you found

your answer.
Mathematics
1 answer:
mash [69]3 years ago
4 0
So it is in (x,y) format so
2=x and 4=y so
4= something 2
4=2 times 2 so one equation is
4=2x
y=2x

4=2+2
so another equation would be y=x+2

2 possible equations are
y=2x or
y=x+2
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If the ratio of purple marbles to orange marbles is 3 to 8, how many orange marbles will I have if I have 48 purple marbles?
sveticcg [70]

Answer:

You will have 128 orange marbles

Step-by-step explanation:

Set this up as an equation

Variable x = number of orange marbles

3/8 = 48/x

Cross multiply

3 × x = 8 × 48

3x = 384

Divide both sides by 3 to isolate the variable

3x ÷ 3 = 384 ÷ 3

1x = 128

x = 128

128 orange marbles

Check work:

Substitute the variable x for the answer

3/8 = 48/128

Cross multiply

3 × 128 = 8 × 48

384 = 384

If the numbers equal, the answer is correct

6 0
3 years ago
Read 2 more answers
On the day of his 18th birthday harry decided to start saving up money regularly starting on that day he could save £30 on the s
Arada [10]

Answer:

£15120

Step-by-step explanation:

60-18= 42  years

42×12= 504 months

504×30=£15120

6 0
3 years ago
Convert r = 8cos θ to rectangular form.
skelet666 [1.2K]

Answer:

D

Step-by-step explanation:

To convert from polar to rectangular form

• x = rcosΘ , y = rsinΘ

• r = \sqrt{x^2+y^2} ⇒ r² = x² + y²

Given

r = 8cosΘ

r = 8 × \frac{x}{r} ( multiply both sides by r )

r² = 8x, hence

x² + y² = 8x ⇒ D

8 0
4 years ago
How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
Write this product in its simplest form -5a•6a^8
timofeeve [1]
The rule for the product of similar bases with exponents:

(a^b)(a^c)=a^(b+c)

(-5*6)(a^1)(a^8)

(-30)(a^(1+8))

-30a^9
6 0
4 years ago
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