In B 5^2 = 25. There is no x anywhere.
In C f(x) = 2/x is a function of a reciprocal, not a quadratic.
In D f(x) = 2x^3 + 3x^2 - 5 is a cubic. A cubic is not a quadratic. The highest power of a quadratic is x^2
That leaves A. When you expand the brackets, you get
3(x^2 + 3x- 4x - 12)
2(x^2 - x - 12) when you remove the brackets you get
2x^2 - 2x - 24. The highest power of x is x^2. This is your quadratic.
A<<<< answer.
Answer:
95
Step-by-step explanation:
Answer:
2x+6=-8(x>=-7), 2x+3<9(x<3), 2x-4<=-8(x<=-2), -x-8>=-5(x<=-3), x+-4<=-3(x<=1)
Step-by-step explanation:
Answer:
No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.
Example:
the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.
10 + 79 + 42 + 88 + 19 + 50 = 288
288 ÷ 6 = 48
1) 4/(1/5)
=4 ÷ 1/5
to divide fractions, multiply by the reciprocal/inverse of 1/5
=4 * 5/1
=20
4) (7/9)/7
=7/9 ÷ 7
to divide fractions, multiply by the reciprocal/inverse of 7
=7/9 * 1/7
multiply numerators; multiply denominators
=(7*1)/(9*7)
=7/63
simplify by 7
=1/9
7) (9/10)/6
= 9/10 ÷ 6
to divide fractions, multiply by the reciprocal/inverse of 6
= 9/10 * 1/6
multiply numerators; multiply denominators
= (9*1)/(10*6)
= 9/60
simplify by 3
= 3/20
ANSWER: 1) 20; 4) 1/9; 7) 3/20
Hope this helps! :)
