Given that a species of beetles grows 32% every year.
So growth rate is given by
r=32%= 0.32
Given that 100 beetles are released into a field.
So that means initial number of beetles P=100
Now we have to find about how many beetles will there be in 10 years.
To find that we need to setup growth formula which is given by
where A is number of beetles at any year n.
Plug the given values into above formula we get:
now plug n=10 years
Hence answer is approx 1606 beetles will be there after 20 years.
Now we have to find about how many beetles will there be in 20 years.
To find that we plug n=20 years
Hence answer is approx 25791 beetles will be there after 20 years.
Now we have to find time for 100000 beetles so plug A=100000
33.174666862=n
Hence answer is approx 33 years.
Answer:
A. 4.1
Step-by-step explanation:
3+4+ 5+ 3+ 4+ 5+ 6+ 7+ 1+ 2+ 3+ 4+ 5+ 6+ 4+ 8+ 4+ 3+ 2= 79
79/ 19 = 4.1
Simplifying
(0.75x + 6) + -1(2.5x + -1.9) = 0
Reorder the terms:
(6 + 0.75x) + -1(2.5x + -1.9) = 0
Remove parenthesis around (6 + 0.75x)
6 + 0.75x + -1(2.5x + -1.9) = 0
Reorder the terms:
6 + 0.75x + -1(-1.9 + 2.5x) = 0
6 + 0.75x + (-1.9 * -1 + 2.5x * -1) = 0
6 + 0.75x + (1.9 + -2.5x) = 0
Reorder the terms:
6 + 1.9 + 0.75x + -2.5x = 0
Combine like terms: 6 + 1.9 = 7.9
7.9 + 0.75x + -2.5x = 0
Combine like terms: 0.75x + -2.5x = -1.75x
7.9 + -1.75x = 0
Solving
7.9 + -1.75x = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7.9' to each side of the equation.
7.9 + -7.9 + -1.75x = 0 + -7.9
Combine like terms: 7.9 + -7.9 = 0.0
0.0 + -1.75x = 0 + -7.9
-1.75x = 0 + -7.9
Combine like terms: 0 + -7.9 = -7.9
-1.75x = -7.9
Divide each side by '-1.75'.
x = 4.514285714
Simplifying
x = 4.514285714
I think the answer is A. Or the answer is A.
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