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3 years ago

What is the answer for $ 199 MP3 player 15% discount

2 answers:

8 0

So discount means taken off
we find 15% of 199 and subtract from 199
% means parts out of 100 so 15%=15/100=1.5/10=.15/1=0.15
'of' means multiply
15% of 199=0.15 times 199=29.85
discount so 199-29.85=169.15
answer is $169.15

kipiarov [429]3 years ago

8 0

You have a discount of 29.85.
199-29.85=169.15

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A large bottle of dragon breath mouthwash cost $5.00 before tax and $5.30 after tax. What is the percentage of the tax?

Alex777 [14]

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4 years ago

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Natali5045456 [20]

I run 1 mile every 6 minutes.
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3 years ago

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Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below:

$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

Now putting 1 in $x$ gives us the limit:

$\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5$

So the answer is 5

3 0

3 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
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tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
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\textit{and now, let's rationalize the denominator}
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\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

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3 years ago

The total number of cats and dogs at the shelteris 125. there are 5 more cats than dogs

juin [17]

If you're looking for the number of dogs (I'm assuming, you didn't specify), all you'd have to do is divide the number by two, then round down to find the number of dogs, then check your answer by adding that number and that number plus 5.

For example, yours would look like 125/6=62.5, and rounding down to 60.

Then check your answer by adding 60 and 65, the number of cats. 60+65=125.

There are 60 dogs inside the kennel.

5 0

4 years ago