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Naily [24]
4 years ago
8

Determine whether the given procedure results in a binomial distribution​ (or a distribution that can be treated as​ binomial).

If the procedure is not​ binomial, identify at least one requirement that is not satisfied. Five different senators from the current U.S. Congress are randomly selected without replacement and whether or not​ they've served over 2 terms is recorded. Does the probability experiment represent a binomial​ experiment? A. ​No, because the experiment is not performed a fixed number of times. B. ​No, because the trials of the experiment are not independent and the probability of success differs from trial to trial. C. ​Yes, because the experiment satisfies all the criteria for a binomial experiment. D. ​No, because there are more than two mutually exclusive outcomes for each trial.
Mathematics
1 answer:
MArishka [77]4 years ago
5 0

Answer:

B. ​No, because the trials of the experiment are not independent and the probability of success differs from trial to trial.

Step-by-step explanation:

The first criterion of a binomial distribution is a fixed number of trials.  Selecting 5 senators means the number of trials is 5, which is a fixed number.

The next criterion is that the trials must be independent.  Selecting the senators without replacement means the trials are dependent, not independent; this means that this is not a binomial distribution.

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Which ordered pair is generated from the equation shown below? y = 3x + 2 A. (3, 11) B. (3, 9) C. (5, 15) D. (2, 4)
yan [13]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
C is clicked but I'm not sure if that is the answer I just clicked one. I need the answer to both.
elena-14-01-66 [18.8K]

Answer:

I believe that B is the correct answer!

Step-by-step explanation:

The (x+5) can cancel

Then in the numerator (x^2-25) can be factored into (x-5)(x+5) through difference of squares.

Then in the denominator the (x-5)^2 can be stretched out to (x-5)(x-5)

Lastly the (x-5) on the top and bottom will cancel resulting in result B

I hope this helped!

3 0
3 years ago
Read 2 more answers
Particle P moves along the y-axis so that its position at time t is given by y(t)=4t−23 for all times t. A second particle, part
sergey [27]

a) The limit of the position of particle Q when time approaches 2 is -\pi.

b) The velocity of particle Q is v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t -\sin \pi t}{(2-t)^{2}} for all t \ne 2.

c) The rate of change of the distance between particle P and particle Q at time t = \frac{1}{2} is \frac{4\sqrt{82}}{9}.

<h3>How to apply limits and derivatives to the study of particle motion</h3>

a) To determine the limit for t = 2, we need to apply the following two <em>algebraic</em> substitutions:

u = \pi t (1)

k = 2\pi - u (2)

Then, the limit is written as follows:

x(t) =  \lim_{t \to 2} \frac{\sin \pi t}{2-t}

x(t) =  \lim_{t \to 2} \frac{\pi\cdot \sin \pi t}{2\pi - \pi t}

x(u) =  \lim_{u \to 2\pi} \frac{\pi\cdot \sin u}{2\pi - u}

x(k) =  \lim_{k \to 0} \frac{\pi\cdot \sin (2\pi-k)}{k}

x(k) =  -\pi\cdot  \lim_{k \to 0} \frac{\sin k}{k}

x(k) = -\pi

The limit of the position of particle Q when time approaches 2 is -\pi. \blacksquare

b) The function velocity of particle Q is determined by the <em>derivative</em> formula for the division between two functions, that is:

v_{Q}(t) = \frac{f'(t)\cdot g(t)-f(t)\cdot g'(t)}{g(t)^{2}} (3)

Where:

  • f(t) - Function numerator.
  • g(t) - Function denominator.
  • f'(t) - First derivative of the function numerator.
  • g'(x) - First derivative of the function denominator.

If we know that f(t) = \sin \pi t, g(t) = 2 - t, f'(t) = \pi \cdot \cos \pi t and g'(x) = -1, then the function velocity of the particle is:

v_{Q}(t) = \frac{\pi \cdot \cos \pi t \cdot (2-t)-\sin \pi t}{(2-t)^{2}}

v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t -\sin \pi t}{(2-t)^{2}}

The velocity of particle Q is v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t -\sin \pi t}{(2-t)^{2}} for all t \ne 2. \blacksquare

c) The vector <em>rate of change</em> of the distance between particle P and particle Q (\dot r_{Q/P} (t)) is equal to the <em>vectorial</em> difference between respective vectors <em>velocity</em>:

\dot r_{Q/P}(t) = \vec v_{Q}(t) - \vec v_{P}(t) (4)

Where \vec v_{P}(t) is the vector <em>velocity</em> of particle P.

If we know that \vec v_{P}(t) = (0, 4), \vec v_{Q}(t) = \left(\frac{2\pi\cdot \cos \pi t - \pi\cdot t \cdot \cos \pi t + \sin \pi t}{(2-t)^{2}}, 0 \right) and t = \frac{1}{2}, then the vector rate of change of the distance between the two particles:

\dot r_{P/Q}(t) = \left(\frac{2\pi \cdot \cos \pi t - \pi\cdot t \cdot \cos \pi t + \sin \pi t}{(2-t)^{2}}, -4 \right)

\dot r_{Q/P}\left(\frac{1}{2} \right) = \left(\frac{2\pi\cdot \cos \frac{\pi}{2}-\frac{\pi}{2}\cdot \cos \frac{\pi}{2} +\sin \frac{\pi}{2}}{\frac{3}{2} ^{2}}, -4 \right)

\dot r_{Q/P} \left(\frac{1}{2} \right) = \left(\frac{4}{9}, -4 \right)

The magnitude of the vector <em>rate of change</em> is determined by Pythagorean theorem:

|\dot r_{Q/P}| = \sqrt{\left(\frac{4}{9} \right)^{2}+(-4)^{2}}

|\dot r_{Q/P}| = \frac{4\sqrt{82}}{9}

The rate of change of the distance between particle P and particle Q at time t = \frac{1}{2} is \frac{4\sqrt{82}}{9}. \blacksquare

<h3>Remark</h3>

The statement is incomplete and poorly formatted. Correct form is shown below:

<em>Particle </em>P<em> moves along the y-axis so that its position at time </em>t<em> is given by </em>y(t) = 4\cdot t - 23<em> for all times </em>t<em>. A second particle, </em>Q<em>, moves along the x-axis so that its position at time </em>t<em> is given by </em>x(t) = \frac{\sin \pi t}{2-t}<em> for all times </em>t \ne 2<em>. </em>

<em />

<em>a)</em><em> As times approaches 2, what is the limit of the position of particle </em>Q?<em> Show the work that leads to your answer. </em>

<em />

<em>b) </em><em>Show that the velocity of particle </em>Q<em> is given by </em>v_{Q}(t) = \frac{2\pi\cdot \cos \pi t-\pi\cdot t \cdot \cos \pi t +\sin \pi t}{(2-t)^{2}}<em>.</em>

<em />

<em>c)</em><em> Find the rate of change of the distance between particle </em>P<em> and particle </em>Q<em> at time </em>t = \frac{1}{2}<em>. Show the work that leads to your answer.</em>

To learn more on derivatives, we kindly invite to check this verified question: brainly.com/question/2788760

3 0
2 years ago
There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes ther
rodikova [14]

Answer: a) Number of nickels, dimes, and quarters are 80, 120, 300 respectively.

b) The coins are worth of 91 dollars i.e. $91 in the piggy bank.

Explanation:

Since we have given that

For every 2 nickels there are 3 dimes ,

So, their ratio will be 2:3

and for every 2 dimes there are 5 quarters.\,

So, their ratio will be 2:5

Now, we'll first find the ratio of nickles to dimes to quarters i.e.

Nickle  Dimes  Quarters

2            3

             2               5

So, it becomes ,

Nickle : Dimes : Quarters

2×2     : 3×2        : 3×5

4         : 6            :  15

Now, let the number of nickle be 4x

Let the number of dimes be 6x

Let the number of quarters  be 15x

According to question,

4x+6x+15x=500\\\\25x=500\\\\x=\frac{500}{25}=20

So, number of nickels is given by

4x=4\times 20=80

Number of dimes is given by

6x=4\times 20=120

Number of quarters is given by

15x=4\times 20=300

As we know that

1\ nickel=5\ cents\\\\1\ dime=10\ cents\\\\1\ quarter=25\ cents

So, According to our question, we get

80\times 5+120\times 10+300\times 25=400+1200+7500=9100\ cents\\\\1\ cent=0.01\ dollar\\\\9100\ cents=9100\times 0.01\ dollars=91\ dollars.

Hence,

a) Number of nickels, dimes, and quarters are 80, 120, 300 respectively.

b) the coins are worth of 91 dollars i.e. $91 in the piggy bank.


7 0
3 years ago
The height of a skydiver jumping out of an airplane is given by h=16t +3200
AVprozaik [17]

Answer:

The answer is yes :)

Step-by-step explanation:

4 0
3 years ago
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