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Flura [38]
3 years ago
5

Which values of x and y are solutions to the open sentence?       4y ≥ 3x + 2   A. x = 3, y = 0   B. x = 4, y = 3   C. x = 6, y

= 5   D. x = 7, y = 5
Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0
Your answer would be C. x = 6, y = 5 i hopethis helps
kobusy [5.1K]3 years ago
5 0
Your answer would be C. x = 6, y = 5
This is because if you plug the numbers in to the inequality, we get:
(4 × 5) ≥ (3 × 6) + 2
20 ≥ 18 + 2
20 ≥ 20
which is correct.

I hope this helps!
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B
Lera25 [3.4K]

Answer:

∠ ABD = 42°

Step-by-step explanation:

∠ ODC = 90° ( angle between tangent and radius )

∠ ADC = 90° - 48° = 42°

The angle between a tangent and a chord is equal to the angle in the alternate segment, that is

∠ ABD = ∠ ADC = 42°

4 0
3 years ago
COMPLATE THE PAYTTERN<br> 3, 3, 5, 8, 13, 21, ( ), ( )
Murljashka [212]

Answer: 3; 3; 5; 8; 13; 21; 34; 55.

Try this option:

Step-by-step explanation:

the sum of the previous terms is the next term:3+5=8; 5+8=13; 8+13=21, then

13+21=34 and 21+34=55.

3 0
1 year ago
Convert the map scale to a unit rate. How many inches represent one mile? Show your work. Interpret the meaning of the unit rate
Veronika [31]
Verbal model: mile/inch=mile/inch

Proportion: 7/8÷3/10=x/1

Solve= 7/8*10/3=x/1

70/24=x/1

70=24x

x=35/12

The unit rate must be \frac{35}{12} miles/ inch
7 0
3 years ago
Two teams A and B play a series of games until one team wins three games. We assume that the games are played independently and
Olenka [21]

Answer:

The probability that the series lasts exactly four games is 3p(1-p)(p^{2} + (1 - p)^{2})

Step-by-step explanation:

For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

We also need to know a small concept of independent events.

Independent events:

If two events, A and B, are independent, we have that:

P(A \cap B) = P(A)*P(B)

What is the probability that the series lasts exactly four games?

This happens if A wins in 4 games of B wins in 4 games.

Probability of A winning in exactly four games:

In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:

Event A: A wins two of the first three games.

Event B: A wins the fourth game.

P(A):

A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(A) = P(X = 2) = C_{3,2}.p^{2}.(1-p)^{1} = 3p^{2}(1-p)

P(B):

The probability that A wins any game is p, so P(B) = p.

Probability that A wins in 4:

A and B are independent, so:

P(A4) = P(A)*P(B) = 3p^{2}(1-p)*p = 3p^{3}(1-p)

Probability of B winning in exactly four games:

In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So

Event A: A wins one of the first three.

Event B: B wins the fourth game.

P(A)

P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(A) = P(X = 1) = C_{3,1}.p^{1}.(1-p)^{2} = 3p(1-p)^{2}

P(B)

B wins each game with probability 1 - p, do P(B) = 1 - p.

Probability that B wins in 4:

A and B are independent, so:

P(B4) = P(A)*P(B) = 3p(1-p)^{2}*(1-p) = 3p(1-p)^{3}

Probability that the series lasts exactly four games:

p = P(A4) + P(B4) = 3p^{3}(1-p) + 3p(1-p)^{3} = 3p(1-p)(p^{2} + (1 - p)^{2})

The probability that the series lasts exactly four games is 3p(1-p)(p^{2} + (1 - p)^{2})

8 0
3 years ago
Why did the kindergartener take her books to the zoo
Aneli [31]
Because she wanted to read instead of looking at the animals. Or the book was about the animals at the zoo.
8 0
2 years ago
Read 2 more answers
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