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Darina [25.2K]
3 years ago
15

X^3+4x^2-9x-36 whats the answer

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

x= -4, -3, 3

Step-by-step explanation:

You must factor this equation.

Once you factor, you get (x+4)(x-3)(x+3)

Set this equal to 0 and solve.

You get -4,-3, and 3.

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Is -9.5 greater than -9.05​
Alexxandr [17]

Answer:

-9.5 would be less than -9.05

3 0
3 years ago
What are the lengths of the legs of a right triangle in which one acute angle measures 19o and the hypotenuse is 15 units long?
WITCHER [35]
x,y-\ lengths\ of\ legs\\\\sin19^\circ=\frac{x}{15}\\\\ sin19^\circ*15=x\\\\0,32*15=x\\\\x=4,8\\\\
y^2+(4,8)^2=15^2\\\\y^2=225-23,04\\\\ y^2=201,96\\\\y=14,2\\\\Legs\ are\ equalt\ to:\ 4,8 \ and\ 14,2.
6 0
4 years ago
Write 10,000 in scientific notation
Semenov [28]
1*10^4
Or
10^4
Either way
3 0
3 years ago
Sin(-180° + θ) = ________
Svet_ta [14]

Answer:

\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)

Step-by-step explanation:

We need to find the value of \sin(-180^o+ \theta)

So let's apply formula

\sin\left(A+B\right)=\sin\left(A\right)\cos\left(B\right)+\sin\left(B\right)\cos\left(A\right)

\sin\left(-180^o+\theta\right)=\sin\left(-180^o\right)\cos\left(\theta\right)+\sin\left(\theta\right)\cos\left(-180^o\right)

\sin\left(-180^o+\theta\right)=0\cdot\cos\left(\theta\right)+\sin\left(\theta\right)\cdot\left(-1\right)

\sin\left(-180^o+\theta\right)=0-\sin\left(\theta\right)

\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)

8 0
3 years ago
What is the measure of this angle?<br> A) 44° <br> B) 56° <br> C) 136° <br> D) 144°
allsm [11]
A) 44 degrees just look at the degree the line segment lands on in the protractor
4 0
4 years ago
Read 2 more answers
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