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Cerrena [4.2K]
3 years ago
12

FACTOR the following quadratic expression: x^2-3x-18. Clearly show your steps OR explain your reasoning and CHECK your answer by

multiplying to get back to the starting expression. A correct answer without a CHECK and work/ explanation will NOT receive full credit! NOTE: Press and hold the SHIFT button and press 6 to make the "^" exponent symbol. Someone plz help its doe in 10 min
Mathematics
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

The factors of x² - 3·x - 18, are;

(x - 6), (x + 3)

Step-by-step explanation:

The given quadratic expression is presented as follows;

x² - 3·x - 18

To factorize the given expression, we look for two numbers, which are the constant terms in the factors, such that the sum of the numbers is -3, while the product of the numbers is -18

By examination, we have the numbers -6, and 3, which gives;

-6 + 3 = -3

-6 × 3 = -18

Therefore, we can write;

x² - 3·x - 18 = (x - 6) × (x + 3)

Which gives;

(x - 6) × (x + 3) = x² + 3·x - 6·x - 18 = x² - 3·x - 18

Therefore, the factors of the expression, x² - 3·x - 18, are (x - 6) and (x + 3)

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Please help! I don't know this!<br><br> ( ( 163 ^ 2 ) ^ 2) * ( 0.045701 - 12 / 2 * 3.357470126 )
zaharov [31]

Step-by-step explanation:

{(163²)²} × (0.045701-12/2×3.357470126)

4330747×-20.0991198

8.70

6 0
3 years ago
I know you’re supposed to change the bounds and break up the integral, but for some reason, I can’t get the 44/3. Can someone ex
tatyana61 [14]

First, look for the zeroes of the integrand in the interval [0, 6] :

x² - 6x + 8 = (x - 4) (x - 2) = 0   ⇒   x = 2   and   x = 4

Next, split up [0, 6] into sub-intervals starting at the zeroes we found. Then check the sign of x² - 6x + 8 for some test points in each sub-interval.

• For x in (0, 2), take x = 1. Then

x² - 6x + 8 = 1² - 6•1 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

• For x in (2, 4), take x = 3. Then

x² - 6x + 8 = 3² - 6•3 + 8 = -1 < 0

so x² - 6x + 8 < 0 over this sub-interval.

• For x in (4, 6), take x = 5. Then

x² - 6x + 8 = 5² - 6•5 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

Next, recall the definition of absolute value:

|x| = \begin{cases}x & \text{for }x \ge0 \\ -x & \text{for }x < 0\end{cases}

Then from our previous analysis, this definition tells us that

|x^2 - 6x + 8| = \begin{cases}x^2 - 6x + 8 & \text{for }0

So, in the integral, we have

\displaystyle \int_0^6 |x^2-6x+8| \, dx = \left\{\int_0^2 - \int_2^4 + \int_4^6\right\} (x^2 - 6x + 8) \, dx

Then

\displaystyle \int_0^2 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_0^2 = \frac{20}3 - 0 = \frac{20}3

\displaystyle \int_2^4 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_2^4 = \frac{16}3 - \frac{20}3 = -\frac43

\displaystyle \int_4^6 (x^2 - 6x + 8) \, dx = \left(\frac13 x^3 - 3x^2 + 8x\right) \bigg|_4^6 = 12 - \frac{16}3 = \frac{20}3

and the overall integral would be

20/3 - (-4/3) + 20/3 = 44/3

3 0
3 years ago
Order the following lost from least to greatest. |-65|, -19, 45, 21.7
makkiz [27]

Answer:

19 21.7 45 65well at least I think soo

3 0
3 years ago
1 point
Fynjy0 [20]

Answer: 140 cm

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Simplify.<br> √50<br> OA. 10√5<br> OB. 2√5<br> OC. 5√2<br> OD. 25√2
Nezavi [6.7K]

Decomposition in factors of 50: 2 · 5².

\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0 ,\:b\ge 0

\sqrt{2\cdot \:5^2}=\sqrt{2}\sqrt{5^2}

\mathrm{Apply\:the\:laws\:of\:exponents}:\quad \sqrt{a^2}=a,\:\quad \:a\ge 0

\sqrt{5^2}=5

=\sqrt{2}\cdot \:5

\bf{=5\sqrt{2} \ === > \ Answer }

Option C

↓

\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{MyHeritage} \end{gathered}$}}}

8 0
2 years ago
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