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azamat
3 years ago
13

What is the slope of the line y= -8

Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0
No slope

If you were to graph it the line would be straight across with no rise
dmitriy555 [2]3 years ago
6 0
Slope would be 0, so basically yea, there’s no slope
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For the<br> expression y + 6-3 determine the coefficient for the variable term.<br> (2 points)
aksik [14]

Answer:

The answer is 1.

Step-by-step explanation:

The number is usually in front of the variable, if there is no number, it is a 1.

6 0
3 years ago
What is the sum of 6/7 and 1/2?
Svetllana [295]

The sum of the fraction 6/7 and 1/2 is 19/14

<h3>How to add fractions</h3><h3 />

Given:

sum of 6/7 and 1/2

Sum means addition(+)

= 6/7 + 1/2

The least common denominator is 7 × 2 = 14

= 6/7 + 1/2

= (12+7) / 14

= 19/14

Therefore, the sum of 6/7 and 1/2 is 19/14

Learn more about fraction:

brainly.com/question/11562149

3 0
2 years ago
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The ratio of the interior angle measures of a triangle is 2:3:5. What are the angle measures?
romanna [79]

Answer:

36:54:90

Step-by-step explanation:

you add all the parts together (2+3+5) which is 10. then you divide 180 by 10 because angles in triangle add up to 180. so 18 is one part

then you just times 18 by each part in the ratio

3 0
2 years ago
John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m
Dmitry [639]

Answer:

The minimum possible initial amount of fish:52

Step-by-step explanation:

Let's start by saying that

x = is the initial number of fishes

John:

When John arrives:

  • he throws away one fish from the bunch

x-1

  • divides the remaining fish into three.

\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}

  • takes a third for himself.

\dfrac{x-1}{3} + \dfrac{x-1}{3}

the remaining fish are expressed by the above expression. Let's call it John

\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}

and simplify it!

\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}

When Joe arrives:

  • he throws away one fish from the remaining bunch

\text{John} -1

  • divides the remaining fish into three

\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}

  • takes a third for himself.

\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

the remaining fish are expressed by the above expression. Let's call it Joe

\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

and simiplify it

\text{Joe}=\dfrac{2}{3}(\text{John}-1)

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)

\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}

When James arrives:

We're gonna do this one quickly, since its the same process all over again

\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}

\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)

\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. <u>We also know that this last pile was a multiple of 3 before a third was taken away by James</u>.

Whatever the last remaining pile was (let's say n), a third is taken away by James. the remaining bunch would be \frac{n}{3}+\frac{n}{3}

hence we've expressed the last pile in terms of n as well.  Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

14=\dfrac{8x}{27} - \dfrac{38}{27}

by solving this equation we'll have the value of x, which as we established at the start is the number of initial amount of fish!

14=\dfrac{8x}{27} - \dfrac{38}{27}

x=52

This is minimum possible amount of fish before John threw out the first fish

8 0
2 years ago
10=12-x what would match this equation
Eddi Din [679]

Answer:

x=2

Step-by-step explanation:

12-10=2

6 0
3 years ago
Read 2 more answers
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