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Jet001 [13]
3 years ago
6

Please Help!! Write the function I'm vertex form y = -x^2-2x+6 y=

Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Rewrite in standard form and use the form to find the vertex.

(1, 5)

(x - 1)^2 + 5

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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
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Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:

f(x)=[1 / (4p)] (x-h)^2+k

where Vertex: V=(h,k)

The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

h=(3+3)/2→h=6/2→h=3

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Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

f(x)=[ 1 / (-8) ] (x-3)^2 + 3

f(x)= - (1/8) (x-3)^2 + 3

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What is the number 2.0847 to 2 decimal places?
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Answer:

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Step-by-step explanation:

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The graph shows y in direct variation with x. Find the value of Y when X=-15
telo118 [61]
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<h3>★ <u>11/30</u> is the right answer. ★</h3>

Step-by-step explanation:

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PART 1
Sloan [31]

the answer has to be C


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