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3 years ago

Identify the pair of angles as corresponding alternate interior, both or neither

Mathematics

2 answers:

aalyn [17]3 years ago

8 0

Answer:

alternate interior angles

Step-by-step explanation:

Identify the pair of angles m<4 and m<7 as corresponding alternate interior, both or neither

we know that

<u>Alternate interior angles</u> are two congruent interior angles which lie on different parallel lines and on opposite sides of a transversal.

$m$ ------> by alternate interior angles

Stella [2.4K]3 years ago

6 0

the right answer is 7 and 4 because the angles are between the two lines that are not the transversal and are on diagonal opposite sides of the transversal.

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Please help this is due today

prisoha [69]

Answer:

x=28°

y=152°

Step-by-step explanation:

x=28°

y=152°

3 0

3 years ago

Simplify the square root of 7+2<br> So 7+2 is inside the quare root

serious [3.7K]

Answer:

Step-by-step explanation:

$\sqrt{7+2}=\sqrt{9}=\sqrt{3^2}=\boxed{3}$

6 0

3 years ago

What is the product (2t+1) (t-4)

____ [38]

Answer:

Step-by-step explanation:

(2t+1)(t-4)

= 2t^2 - 8t + t - 4

= 27^2 - 7t - 4

3 0

3 years ago

If a stadium has 15,000 seats sold at $10.00, $12.50, and $15.00 equally distributed in three sections, how much can be made if

ELEN [110]

If it is equally distrubuted in 3 sections then we would divide 15,000 by 3. Now we take one section which would cost $10.00 and multiply it by the 5,000 since we divided. We would do the same with all three and then add it together.

$10 * 5,000 = $50,000 section one can sell this much
$12.50 * 5,000 = $62,500 section two can sell this much
$15 * 5,000 = $75,000 section three can sell this much

If all the seats are sold than 50k + 62.5k + 75k = $187,500 can be made

3 0

3 years ago

AD= 36 cm. Points C, B∈AD, such that AB:BC:CD=2:3:4. Find the distance of midpoints of the segments AB and CD.

brilliants [131]

Answer:

The distance of the midpoints of AB and CD is 24 cm

Step-by-step explanation:

The given information are;

The length of AD = 36 cm.

C and B are points on AD

The ratio of AB:BC:CD 2:3:4

The distance of the midpoints of segments AB and CD required

Therefore, we have the following proportion of the total length, 36

Segment AB = 2/(2 + 3 + 4) = 2/9×36 = 8 cm

Segment BC = 3/(2 + 3 + 4) = 3/9×36 = 12 cm

Segment CD = 4/(2 + 3 + 4) = 4/9×36 = 16 cm

The x-coordinate of the midpoint of segment AB = 4 cm

The x-coordinate of the midpoint of segment CD = 8 + 12 + 16/2 = 28 cm

Which gives;

The distance of midpoint of segment AB from A = 4 cm

The distance of midpoint of segment CD from A = 28 cm

And the distance of the midpoints of AB and CD = 24 - 4 = 24 cm.

4 0

3 years ago