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vlabodo [156]
3 years ago
12

The question is in the file

Mathematics
1 answer:
Basile [38]3 years ago
5 0

Answer:

0.00024

Step-by-step explanation:

= 2.4 × 10-4

(scientific notation)

= 2.4e-4

(scientific e notation)

= 240 × 10-6

(engineering notation)

(millionth; prefix micro- (u))

= 0.00024

(real number)

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What equation results from completing the square and then factoring? x^2+24x=33
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Answer:

Its C but the way I got is too small so I cant really give explanation

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Please need help I will be MARKING as BRIANILIST. thank you so much. ​
Marina86 [1]

Answer:

a. (3,11) (4,15) (5,19) (6,23)

b. it's not proportional because b (from y=mx+b) is not 0

c. the equation is y = 4x - 1

d. graph the y-int (-1) on the y-intercept and then connect the points in a.

Step-by-step explanation:

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3 years ago
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Phoenix [80]

Answer:

The answer is 3

Step-by-step explanation:

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2 years ago
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M∠a=(48−x)°m∠b=(9x−38)°m∠c=90°
Pachacha [2.7K]

<u>The question does not specify the condition that must satisfy the given angles. We assume they are the internal angles of a triangle.</u>

Answer:

<em>x = 10</em>

Step-by-step explanation:

<u>Internal Angles of a Triangle</u>

The measure of the angles of a triangle are given as 48-x, 9x-38, and 90. Since the sum of the internal angles of a triangle is 180°:

48 - x + 9x - 38 + 90 = 180

Simplifying:

100 + 8x = 180

Subtracting 100:

8x = 180 - 100 = 80

x = 80/8

x = 10

7 0
3 years ago
Show that the points (0.-1).(2, 1).(0.3) and (-2, 1) are the vertices of a square ABCD.
Inessa05 [86]

The diagram is below

  • A = (0,-1)
  • B = (2,1)
  • C = (0,3)
  • D = (-2,1)

Let's find the distance from A to B using the distance formula.

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-2)^2 + (-1-1)^2}\\\\d = \sqrt{(-2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\d \approx 2.828\\\\

The distance from A to B is exactly \sqrt{8} units or approximately 2.828 units. This is the length of side AB.

Through very similar steps, you should find that the other side lengths of BC, CD and AD are all the same.

Since AB = BC = CD = AD, this means we have a rhombus. Recall a rhombus is any quadrilateral with all four sides the same length.

-----------------------------

Let's find the slope of line AB

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{1 - (-1)}{2 - 0}\\\\m = \frac{1 + 1}{2 - 0}\\\\m = \frac{2}{2}\\\\m = 1\\\\

Line AB has a slope of 1.

Through similar steps, you should find the slope of line BC is -1.

Rule: Whenever two slopes multiply to -1, then their corresponding lines are perpendicular.

Based on that rule, lines AB and BC are perpendicular. This means they meet up at a right angle (aka 90 degree angle).

You should find that line CD has a slope of 1, so BC and CD are perpendicular. Lastly, line AD has a slope of -1. So all the slopes mentioned are either +1 or -1. The slopes alternate as you move around the figure. This all shows that any two adjacent sides meet at a 90 degree angle.

Therefore, this figure is a rectangle. Any rectangle has all four angles of 90 degrees.

-----------------------------

The first section showed that we have a rhombus. The second section afterward showed that we also have a rectangle. The combination of a rhombus and a rectangle at the same time leads to a square.

Therefore, quadrilateral ABCD is a square.

5 0
2 years ago
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