Answer:
TT→T
Step-by-step explanation:
If p is false, then ~p is true.
If q is false, then ~q is true.
Now note that
- If a and b are both true, then a→b is true.
- If a is true, b is false, then a→b is false.
- If a is false, b is true, then a→b is true.
- If a and b are both false, then a→b is true.
In your case, both~p and ~q are true, then ~p→~q is true too (or TT→T)
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
The correct numbers to use in solving problems about
spans of time like B.C. and A.D. should be “integers”.
Integers are whole numbers (not a fractional number or not a decimal
number) which can take a value of negative, zero, or positive number. Example
of integers would be -1, 0 and 1.
<span>In calculations, the time period would be on the x-axis. Since
B.C. and A.D. are two different spans of time, therefore in the calculations,
the date of BC should be negative (negative x-axis) while the date of AD should
be positive (positive x-axis). This would place the origin as the common
reference.</span>
In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m
