I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.



Answer: n² - 3n - 20 = 0
That doesn't factor so there is no integer n solution.
That means there are no polygons with 10 diagonals.

The answer to your question is 74/99:D
All good and for number 6 you should draw an acute angle
Answer:
I want to show you how to do this as well, the formula you are working with is a^2+b^2=c^2
Step-by-step explanation:
1.) 8^2+b^2=12^2
64+b^2=144
subtract 64 from both sides
b^2=80
take the square root of 80 and you get
b= 8.9
if you need more help on this let me know, I am going to list the other answers now because to do it all and show work on here is a lot of typing, all of which I will do if you do not understand the first example. Also the c value can ONLY BE THE HYPOTENUSE VALUE. The hypotenuse is the longest side of the triangle. For example, 12 would be the C value on number one and in number two it would be 15.
2.) 14.5
3.) 10.3
4.) 18.8
5.) 8
6.) 15
Answer:
(4×9+5) -10+16×6
36 + 5 - 10 + 16 * 6
41 - 10 + 96
41 + 86
127
Step-by-step explanation:
(4×9+5) -10+16×6
36 + 5 - 10 + 16 * 6
41 - 10 + 96
41 + 86
127
use PEMDAS
p = parantheses
e= exponent
m = multiply
d = divide
a = add
s = subtract