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nalin [4]
2 years ago
7

Help me on this math thing

Mathematics
1 answer:
deff fn [24]2 years ago
7 0

a) \frac{6}{3}+9=2+9=\boxed{11} \\ \\ b) 8(2)-3+1=\boxed{14} \\ \\ c) 2(5)(-3)=\boxed{-30} \\ \\ d) 2(3)^2-8=2(9)-8=18-8=\boxed{10}

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Answer:

m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]

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<u>Calculate the value of H</u>

Given:

\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)

Therefore:

\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />

<u>Calculating m × H</u>

<u />

<u />\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]

<u />\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]

\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]<u />

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