if £500 is invested for 3 years at a rate of compound interest of 4% per annum how much will be in the account after three years
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You solve the equation : t^2 - 9t - 90 = 0 ;
Δ = ( - 9 )^2 - 4 * 1 * ( - 90 ) = 81 + 360 = 441 ;
t1 = ( 9 +
) / 2 = 30 / 2 = 15 ;
t2 = ( 9 -) / 2 = -12 / 2 = - 6 ;
The numbers are 15 and - 6 ;
Δ = ( - 9 )^2 - 4 * 1 * ( - 90 ) = 81 + 360 = 441 ;
t1 = ( 9 +
t2 = ( 9 -
The numbers are 15 and - 6 ;
Start off by "switching" the variables
then solve for "y"
then solve for "y"