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4 years ago

Ving Advanced Linear Equations: Practice

Mathematics

1 answer:

Nastasia [14]4 years ago

3 0

Answer:

In the first week, Micah bought 11 gallons of gas.

In the second week, Micah bought 8 gallons of gas.

Step-by-step explanation:

Given:

First week

x gallons of gas at $2.39 per gallon

x gallons = $2.39x

Second week

3 fewer gallons of gas than the first week at $2.49 per gallon

x - 3 gallons = $2.49(x-3)

Total spent = $46.21

$2.39x + $2.49(x-3) = $46.21

2.39x + 2.49x - 7.47 = 46.21

4.88x - 7.47 = 46.21

Add 7.47 to both sides

4.88x - 7.47 + 7.47 = 46.21 + 7.47

4.88x = 53.68

Divide both sides by 4.88

x = 53.68/4.88

= 11

x = 11

First week = x = 11 gallons

Second week

= x - 3

= 11-3

= 8 gallons

Therefore,

In the first week, Micah bought 11 gallons of gas.

In the second week, Micah bought 8 gallons of gas.

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sladkih [1.3K]

Consider the right triangle in the attached diagram. Using the Pythagorean theorem, you can find the distance marked "a" by
r² = a² + o²
a = √(r² - o²) = √(20² -16²)
a = √(400 - 256) = √144 = 12

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4 years ago

Could someone please help me:) I am stick and I am not sure what to do

Delicious77 [7]

Answer:

Part 5.1.1:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

We are given that:

$\displaystyle \sin 2A = \frac{\sqrt{15}}{8}$

Part 5.1.1

Recall that:

$\displaystyle \sin^2 \theta + \cos^2 \theta = 1$

Let θ = 2A. Hence:

$\displaystyle \sin ^2 2A + \cos ^2 2A = 1$

Square the original equation:

$\displaystyle \sin^2 2A = \frac{15}{64}$

Hence:

$\displaystyle \left(\frac{15}{64}\right) + \cos ^2 2A = 1$

Subtract:

$\displaystyle \cos ^2 2A = \frac{49}{64}$

Take the square root of both sides:

$\displaystyle \cos 2A = \pm\sqrt{\frac{49}{64}}$

Since 0° ≤ 2A ≤ 90°, cos(2A) must be positive. Hence:

$\displaystyle \cos 2A = \frac{7}{8}$

Part 5.1.2

Recall that:

$\displaystyle \begin{aligned} \cos 2\theta &= \cos^2 \theta - \sin^2 \theta \\ &= 1- 2\sin^2\theta \\ &= 2\cos^2\theta - 1\end{aligned}$

We can use the third form. Substitute:

$\displaystyle \left(\frac{7}{8}\right) = 2\cos^2 A - 1$

Solve for cosine:

$\displaystyle \begin{aligned} \frac{15}{8} &= 2\cos^2 A\\ \\ \cos^2 A &= \frac{15}{16} \\ \\ \cos A& = \pm\sqrt{\frac{15}{16}} \\ \\ \Rightarrow \cos A &= \frac{\sqrt{15}}{4}\end{aligned}$

In conclusion:

$\displaystyle \cos A = \frac{\sqrt{15}}{4}$

(Note that since 0° ≤ 2A ≤ 90°, 0° ≤ A ≤ 45°. Hence, cos(A) must be positive.)

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3 years ago

Jill gets a base pay of $1500 per month. She also earns a commission of 8% of her total sales. What are Jill's earnings for a mo

mart [117]

Answer:

$4060.

Step-by-step explanation:

We have been given that Jill gets a base pay of $1500 per month. She also earns a commission of 8% of her total sales. We are asked to find Jill's earnings for a month in which she has sales of $32,000.

Jill's earnings for the month would be base salary pus 8% of $32,000.

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