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max2010maxim [7]
3 years ago
12

The owner of a small firm has just purchased a personal computer, which she expects will serve her for the next two years. The o

wner has been told that she "must" buy a surge suppressor to provide protection for her new hardware against possible surges or variations in the electrical current, which have the capacity to damage the computer. The amount of damage to the computer depends on the strength of the surge. It has been estimated that there is a 1% chance of incurring 550 dollar damage, 6% chance of incurring 150 dollar damage, and 15% chance of incurring 100 dollar damage from a surge within the next two years. An inexpensive suppressor, which would provide protection for only one surge, can be purchased. How much should the owner be willing to pay if she makes decisions on the basis of expected value?
Mathematics
2 answers:
timurjin [86]3 years ago
5 0

Answer: The owner should not spend more than $29.95 for the surge.

Step-by-step explanation:

Hi, to answer this question we have to multiply each probability by the cost incurred, and then add the results.

1% chance of incurring 550 dollar damage = (1/100) 550 = $5.5

6% chance of incurring 150 dollar damage = (6/100) 150 =$ 9

15% chance of incurring 100 dollar damage = (15/100) 100 = $15

Expected value of repairs: $5.5 +$9+$15 =$29.5

The owner should not spend more than $29.95 for the surge.

tatiyna3 years ago
4 0

Answer: 26 dollars

Step-by-step explanation:

The owner needs to consider that:

To measure the risk she can multiply the probability of an event to happen  (P)* the impact (I) (in this case the impact is the cost).

All these eventes can be considered as independent between each other (no correlation), so you can add their  P*I.

In this case:

P1*I1= 1%*550=5.5

P2*I2=6%*150=9

P3*I3=15%*100=15

So, the expected value of what she may spend for repairng is = P1*I1+P2*I2+P3*I3= 5.5+9+15= 29.5

She shoould not spend more than 29.5 dollars, otherwise,  she will spend more in the surge supresor than in expected reapring value

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The function f(x) = –x2 + 20x – 75 models the profit from one customer, in dollars, a shop makes for printing photos, where x is
trasher [3.6K]
The function is graphed as shown below

Part A:

We use the formula - \frac{b}{2a} to find the vertex of the function. A quadratic function of the form of a x^{2} +bx+c and equating this form to the given function - x^{2} +20x-75, we have
b=20 and a=-1.

Substituting a and b into the vertex formula, we have
x=- \frac{20}{2(-1)}=10, as shown in the graph

This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos

Part B:

We can find solution to this equation by factorising

- x^{2} +20x-75=0
-( x^{2} -20x+75)=0
x^{2} -20x+75=0
(x-5)(x-15)=0
x=5 and x=15, as shown in the graph

The two values means that the company makes no profit when they either produce 5 or 15 photos

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3 years ago
What is the center of a circle represented by the equation ( x + 9)2 + ( y + 6 )2= 10^2
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Answer:

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Step-by-step explanation:

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3 years ago
find the value of q for which point p(q,2) is the midpoint of the line segment joining the points q(-5,0) and r(-1,4)​
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6 0
3 years ago
I don’t know what the anwsered would be i don’t understand this module
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Answer:25,000(0.15)^x

Step-by-step explanation:

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In the diagram, TC represents a vertical building. The points, A and B, are on the same level as the foot C of the building such
Alenkinab [10]

Answer:

(a) The height of the building is 60.06 m

(b) The distance AB is 139.43 m

Step-by-step explanation:

The given parameters are

Given that segment BT = segment AT + 29

By trigonometric ratios, we have;

cos∠ATC = CT/AT

cos∠BTC = CT/BT

Therefore, we have;

cos(40°) = CT/AT.................................(1)

cos(56°) = CT/BT = CT/(AT + 29).....(2)

cos(56°) = CT/(AT + 29)......................(3)

From equation (1)

CT = AT×cos(40°)

From equation (3)

AT×cos(56°) + 29 × cos(56°) = CT

Therefore;

AT×cos(40°) = AT×cos(56°) + 29 × cos(56°)

AT×cos(40°) - AT×cos(56°) =  29 × cos(56°)

AT×(cos(40°) - cos(56°)) =  29 × cos(56°)

AT = 29 × cos(56°)/(cos(40°) - cos(56°)) = 78.4 m

TC = CT = AT×cos(40°) = 78.4×cos(40°) = 60.06 m

The height of the building = 60.06 m

(b) BT = AT + 29 = 78.4 m + 29 m= 107.4 m

AB = AT×sin(∠ATC ) + BT×sin(∠BTC) = 78.4×sin(40°) + 107.4×sin(56°) =  139.43 m

The distance AB =  139.43 m.

6 0
3 years ago
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