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lys-0071 [83]
3 years ago
8

Solve the inequality.

Mathematics
1 answer:
kaheart [24]3 years ago
7 0
I hope this helps you





-2p <20-4



-2p <16


-2p/-2 <16/-2


p> -8
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Help me fill this out thanks
alukav5142 [94]

Answer:

This is an isosceles right triangle, then we have

2 x u^2 = [6sqrt(2)]^2

<=> 2 x u^2 = 72

<=> u^2 = 36

<=> u = 6

Hope this helps!

:)

8 0
3 years ago
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
Find he slope of the following equation for a line:<br> 12x-4y=16
Annette [7]
12x-4y=16
Isolate Y: 
Subtract 12x from both sides 
-4y=-12x+16
Divide by -4 
y=3x-4
Therefore the slope is 3
4 0
3 years ago
What’s 20% Of 1 million
ser-zykov [4K]
200,000 is 20% of 1,000,000
4 0
3 years ago
Read 2 more answers
How to tell if an equation is linear without graphing
Inessa05 [86]

Answer:

A linear equation has the greatest x power at 1.

If you see an equation with only x (no x^2 or x^3 or stuff like that), you will know that it is linear.

7 0
2 years ago
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