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qwelly [4]
4 years ago
12

Write an expression equal to 7³​

Mathematics
1 answer:
MAVERICK [17]4 years ago
5 0
7 x 7 x 7 is the answer
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I need help with this please
kodGreya [7K]
1/5(2x - 10) + 4x = -3(1/5x + 4)
0.4x - 2 + 4x = -0.6x - 12
4.4x - 2 = -0.6x - 12
5x - 2 = -12
5x = -10
x = -2
6 0
3 years ago
Read 2 more answers
Evaluate 5.5r8.35s when r12 and s4.
Over [174]

Answer:

32.6

Step-by-step explanation:

when you plug in for s and r you will get 66-33.4 since 5.5 multiped by 12 is 66 and 8.35 multiplied by 4 is 33.4 .

then you subtract them and that's how you'll get your answer

3 0
3 years ago
I posted a question similar to this but I entered it wrong too many times :(
slava [35]

Answer:

\sqrt[4]{\frac{5}{7} }

Step-by-step explanation:

^4√5/^4√7

~Apply radical rules

^4√5/7

Best of Luck!

5 0
3 years ago
Read 2 more answers
Consider two people being randomly selected. (For simplicity, ignore leap years.)
inna [77]

Answer:

(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

=\frac{12}{365} X\frac{12}{365}  = \frac{144}{133225}

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on  same day of same month) = 1

P(2 people selected not having birthday on  same day of same month):

= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}

P(2 people selected have birthday on the same day of same month) = 1-\frac{364}{365} \\\\= \frac{1}{365}

7 0
3 years ago
What does a reminder means in the context of the problem
Aleonysh [2.5K]
What ever solution is left over after solved 
5 0
3 years ago
Read 2 more answers
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