Answer:
25t = 65
Step-by-step explanation:
Given that :
Profit earned = $60
Charge per hour = $25
Randy's cost or expenses = $(2 + 3) = $5 per job
Profit = (charge per hour * t) - cost
Where t = time
$60 = ($25 * t) - $5
$60 = $25t - $5
$25t = $65
Answer:
x=-1/85; y=-283/85; z=2/17
Step-by-step explanation:
Using an algebraic method like elimination or substitution would take a lot of steps which could lead to mistake the calculations. In this case, I decided to use the Gaussian elimination. We can express the system in matrix form as follows:
![\left[\begin{array}{ccc}2&-4&6\\9&-3&1\\5&0&9\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}14\\10\\1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%266%5C%5C9%26-3%261%5C%5C5%260%269%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D14%5C%5C10%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To begin the calculations, we write the system in augmented matrix form and use the Gaussian elimination:
![\left[\begin{array}{ccccc}2&-4&6&|&14\\9&-3&1&|&10\\5&0&9&|&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D2%26-4%266%26%7C%2614%5C%5C9%26-3%261%26%7C%2610%5C%5C5%260%269%26%7C%261%5Cend%7Barray%7D%5Cright%5D)
By applying the Gaussian elimination, the final matrix is the following:
![\left[\begin{array}{ccccc}1&0&0&|&-1/85\\0&1&0&|&-283/85\\0&0&1&|&2/17\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%260%260%26%7C%26-1%2F85%5C%5C0%261%260%26%7C%26-283%2F85%5C%5C0%260%261%26%7C%262%2F17%5Cend%7Barray%7D%5Cright%5D)
In order to verify the results, it´s enough to substitute the calculated values in the original equations to see if the equalities are correct. Here you can see the verification for all of the equations:

Probability = (number of ways to succeed) / (total possible outcomes) .
The total possible results of rolling two dice is
(6 on the first cube) x (6 on the second one) = 36 possibilities.
How many are successful ? I need you to clarify something first.
You said that the 'second die' shows an odd number. When a pair
of dice is rolled, the problem usually doesn't distinguish between them.
And in fact, you said that they're "tossed together" (like a spinach and
arugula salad ?) so I would understand that they would lose their identity
unless they were, say, painted different colors, and we wouldn't know
which one is the second one.
Oh well, I'll just work it both ways:
First way:
Two identical dice are tossed.
The total is 5 and ONE cube shows an odd number.
How can that happen ?
1 ... 4
4 ... 1
3 ... 2
2 ... 3
Four possibilities. Probability = 4/36 = 1/9 = 11.1% .
=======================================
Second way:
A black and a white cube are tossed together.
The total is 5 and the white cube shows an odd number.
How can that happen:
B ... W
4 .... 1
2 .... 3
Only two possibilities. Probability = 2/36 = 1/18 = 5.6% .
Answer:
(
+4)-3
Step-by-step explanation:
since it says "and four" i think it means it is in parenthesis