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inna [77]
4 years ago
8

The present ratio of students to teachers at a certain school is 30 to 1. If the student enrollment were to increase by 50 stude

nts and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1.
What is the present number of teachers?
Mathematics
1 answer:
disa [49]4 years ago
5 0

Answer: 15

Step-by-step explanation:

Given: The present ratio of students to teachers at a certain school is 30 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1.

To Find: What is the present number of teachers.

Solution:

let the number of teachers in schools are =\text{x}

As the current ratio of students to teachers is 30 to 1

Number of students in school are   =30\text{x}

Now,

If number of student enrollment and teachers were to increase by 50 and 5 respectively.

New number of students in school would be  =30\text{x}+50

New number of teacher in school would be \text{x}+5

new ratio of students to teachers is 25:1

            \frac{30\text{x}+50}{\text{x}+5}=\frac{25}{1}

            30\text{x}+50=25\text{x}+125

            5\text{x}=75

            \text{x}=15

Hence the number of teachers in school is 15

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5 0
3 years ago
Randi shovels and salts her neighbors' driveways and walkways to earn money during the winter months in her town near the Pocono
grin007 [14]

Answer:

25t = 65

Step-by-step explanation:

Given that :

Profit earned = $60

Charge per hour = $25

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Profit = (charge per hour * t) - cost

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7 0
3 years ago
The system of equations is given:
Nutka1998 [239]

Answer:

x=-1/85; y=-283/85; z=2/17

Step-by-step explanation:

Using an algebraic method like elimination or substitution would take a lot of steps which could lead to mistake the calculations. In this case, I decided to use the Gaussian elimination. We can express the system in matrix form as follows:

\left[\begin{array}{ccc}2&-4&6\\9&-3&1\\5&0&9\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}14\\10\\1\end{array}\right]

To begin the calculations, we write the system in augmented matrix form and use the Gaussian elimination:

\left[\begin{array}{ccccc}2&-4&6&|&14\\9&-3&1&|&10\\5&0&9&|&1\end{array}\right]

By applying the Gaussian elimination, the final matrix is the following:

\left[\begin{array}{ccccc}1&0&0&|&-1/85\\0&1&0&|&-283/85\\0&0&1&|&2/17\end{array}\right]

In order to verify the results, it´s enough to substitute the calculated values in the original equations to see if the equalities are correct. Here you can see the verification for all of the equations:

2(-1/85)-4(-283/85)+6(2/17)=14\\9(-1/85)-3(-283/85)+1(2/17)=10\\5(-1/85)+9(2/17)=1

6 0
3 years ago
Two dice are tossed together. What is the probability of getting an odd number on the second die and a total of five?
wolverine [178]

Probability = (number of ways to succeed) / (total possible outcomes) .

The total possible results of rolling two dice is

   (6 on the first cube) x (6 on the second one) = 36 possibilities.

How many are successful ?  I need you to clarify something first.
You said that the 'second die' shows an odd number.  When a pair
of dice is rolled, the problem usually doesn't distinguish between them. 
And in fact, you said that they're "tossed together" (like a spinach and
arugula salad ?) so I would understand that they would lose their identity
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Oh well, I'll just work it both ways:

First way: 
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How can that happen ?

1 ... 4
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Four possibilities.  Probability = 4/36 = 1/9 = 11.1% .

=======================================

Second way:
 
A black and a white cube are tossed together.
The total is 5 and the white cube shows an odd number.

How can that happen:

B ... W
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Only two possibilities.  Probability = 2/36 = 1/18 = 5.6% .

3 0
4 years ago
3 fewer than a number squared and four
grigory [225]

Answer:

(n^{2}+4)-3

Step-by-step explanation:

since it says "and four" i think it means it is in parenthesis

5 0
3 years ago
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