If a function has a vertical asymptote at a certain x-value, then the function is _____ at that value.

Mathematics

2 answers:

Dmitriy789 [7]3 years ago

8 0

The denominator of the function would be equal to zero so it would be undefined.

cluponka [151]3 years ago

6 0

Answer:zero

Step-by-step explanation:

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Solve for r. s=2πrh

Butoxors [25]

Answer:

s/2πh =r

Step-by-step explanation:

s=2πrh

Divide both sides by 2πh to isolate r

s/2πh =2πrh /2πh

s/2πh =r

8 0

3 years ago

Lim <br> x → 1 <br> ln(x)/<br> sin(7πx)

mote1985 [20]

$\displaystyle\lim_{x\to1}\frac{\ln x}{\sin7\pi x}$

Note that both the numerator and denominator approach 0 as $x\to1$ , so we can try using L'Hopital's rule.

$\displaystyle\lim_{x\to1}\frac{\lnx }{\sin7\pi x}=\lim_{x\to1}\frac{\frac1x}{7\pi\cos7\pi x}=\lim_{x\to1}\frac1{7\pi x\cos7\pi x}$

The denominator is nonzero at $x=1$ , so the limit is equivalent to

$\displaystyle\frac1{\lim\limits_{x\to1}7\pi x\cos7\pi x}=\frac1{7\pi\cos7\pi}=-\frac1{7\pi}$