A particle moves so that r(t) = ati + b sin atj. Show that the magnitude of the acceleration of the particle is proportional to
its distance from the x-axis.
2 answers:
Answer:
Step-by-step explanation:
Given
Position of particle is
i.e. distance from x axis is
Distance from y axis at
velocity is given by
Similarly acceleration is given by
Magnitude of acceleration is
From 1 and 2 we can see that
Magnitude of acceleration is proportional to distance from x axis
Answer:
Step-by-step explanation:
The displacement function is given by
.... (1)
Differentiate both sides with respect to t on both the sides
Differentiate again with respect to t to get the function of acceleration
where, A is the acceleration
So, by equation (1)
So, the acceleration is proportional to the displacement function.
You might be interested in
Answer:
x^2+8x+15
Step-by-step explanation:
You can use FOIL method
(x*x)+(x*5)+(3*x)+(3*5)
x^2+5x+3x+15
x^2+8x+15
Answer: 1/3
Step-by-step explanation:
1/4+5/12=3/12+5/12=8/12
1-8/12=4/12=1/3
Answer:
<h2>0.23333333333</h2>
Step-by-step explanation:
<h2>in simpliest form is 0.23</h2>
Answer:
what do you mean
Step-by-step explanation:
please explain
Answer: the answer to ur question is A. Hope this helps plz mark brainliest:)
Step-by-step explanation: