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3 years ago

Does a charge battery have potential energy

Mathematics

1 answer:

vovangra [49]3 years ago

3 0

I’m pretty sure it has potential energy. Because a charge battery can be charged. So it can have energy

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Find the unit tangent vector T and the principal unit normal vector N for the following parameterized curve.

const2013 [10]

Answer:

$T(t) = ( -sin(t^2), cos(t^2) )\\\\N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

Step-by-step explanation:

Remember that for any curve $r(t)$

The tangent vector is given by

$T(t) = \frac{r'(t) }{| r'(t)| }$

And the normal vector is given by

$N(t) = \frac{T'(t)}{|T'(t)|}$

For this case, using the chain rule

$r'(t) = ( -10*2tsin(t^2) , 102t cos(t^2) )\\$

And also remember that

$|r'(t)| = \sqrt{(-10*2tsin(t^2))^2 + ( 10*2t cos(t^2) )^2} \\\\ = \sqrt{400 t^2*( sin(t^2)^2 + cos(t^2) ^2 })\\=\sqrt{400t^2} = 20t$

Therefore

$T(t) = r'(t) / |r'(t) | = ( -10*2tsin(t^2) , 10*2t cos(t^2) )/ 20t\\\\ = ( -10*2tsin(t^2)/ 20t , 10*2t cos(t^2) / 20t )\\= ( -sin(t^2), cos(t^2) )$

Similarly, using the quotient rule and the chain rule

$T'(t) = ( -2t cos(t^2) , -2t sin(t^2))$

And also

$|T'(t)| = \sqrt{ ( -2t cos(t^2))^2 + (-2t sin(t^2))^2} = \sqrt{ 4t^2 ( ( cos(t^2))^2 + ( sin(t^2))^2)} = \sqrt{4t^2} \\ = 2t$

Therefore

$N(t) = T'(t) / |T'(t) | = (-cos(t^2) , -sin(t^2))$

Notice that

1. $|N(t)| = |T(t) | = \sqrt{ cos(t^2)^2 + sin(t^2)^2 } = \sqrt{1} = 1$

2. $N(t)*T(T) = cos(t^2) sin(t^2 ) - cos(t^2) sin(t^2 ) = 0$

Simlarly

$r'(t) = (2t,-6,0) \\$

and

$|r'(t)| = \sqrt{(2t)^2 + 6^2} = \sqrt{4t^2 + 36}$

Therefore

$T(t) =r'(t)/|r'(t)| = (2t/ \sqrt{4t^2 + 36} , -6/\sqrt{4t^2 + 36},0)$

Then

$T'(t) = (9/(9 + t^2)^{3/2} , (3 t)/(9 + t^2)^{3/2},0)$

and also

$|T'(t)| = \sqrt{ ( (9/(9 + t^2)^{3/2} )^2 + ( (3 t)/(9 + t^2)^{3/2})^2 + 0^2 }\\= 3/(t^2 + 9 )$

And since

$N(t) =T(t)/|T'(t)| = (3/(9 + t^2)^{1/2} , t/(9 + t^2)^{1/2},0)$

6 0

2 years ago

On a coordinate plane, 2 triangles are shown. The first triangle has points A (1, 4), B (3, 4), C (3, 2). The second triangle ha

maw [93]

Answer:

R0, 90°

Step-by-step explanation:

6 0

2 years ago

Find the value of y.<br><br> m ∠ 1 = 3y - 6

Ivenika [448]

$m\angle1=90\\
3y-6=90\\
3y=96\\
y=32$

4 0

3 years ago

Read 2 more answers

What is the value expression 8+24 divided by (2 times 6) - 4

Sphinxa [80]

Answer:

Step-by-step explanation:

Given mixed operations there is a particular order that must be followed.

Using the order set out in the acronym PEMDAS

P - Parenthesis ( brackets ), E- Exponents ( powers ), M - Multiplication, D - Division, A- Addition, S - Subtraction

8 + 24 ÷ (2 × 6) - 4

= 8 + 24 ÷ 12 - 4 ← parenthesis

= 8 + 2 - 4 ← division

= 10 - 4 ← addition

= 6 ← subtraction

6 0

2 years ago

Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and

Ahat [919]

Step-by-step explanation:

With each draw, the probability of selecting a green marble is 2/3 and the probability of selecting a yellow marble is 1/3.

To pick two of the the same color, they can either pick green twice or yellow twice.

P = (2/3)(2/3) + (1/3)(1/3)

P = 5/9

To pick two different colors, they can either pick green first then yellow, or yellow first then green.

P = (2/3)(1/3) + (1/3)(2/3)

P = 4/9

Expected value for Derek is:

D = (5/9)(-1) + (4/9)(1)

D = -1/9

The expected value for Mia is:

M = (5/9)(1) + (4/9)(-1)

M = 1/9

5 0

2 years ago