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Nina [5.8K]
3 years ago
15

Expression for all solutions to the equation cos(theta) = 1 + 3cos(theta)

Mathematics
1 answer:
OleMash [197]3 years ago
7 0
\cos\theta=1+3\cos\theta\implies 0=1+2\cos\theta\implies \cos\theta=-\dfrac12

On the unit cirlce, the cosine of an angle is negative whenever the angle falls in the interval \dfrac\pi2.

If you recall your special triangles, this cosine occurs for angles of x=\dfrac{2\pi}3 and x=\dfrac{4\pi}3.

More generally, this occurs for x=\dfrac{2\pi}3+2n\pi and x=\dfrac{4\pi}3+2n\pi, where n is an integer.
You might be interested in
In 2010, the population of a city was 241,000. From 2010 to 2015, the population grew by 5%. From 2015 to 2020, it fell by 4%. T
lawyer [7]

Answer:

242, 900 people

Step-by-step explanation:

To begin, it says that the population grew by 5%.

(241000)(1.00 + 0.05) = <em>population of the city in 2015</em>

(241000)(1.05) = 253050

253050 is the population of the city in 2015. From 2015 to 2020 it fell four percent.

(253050)(1.00 - 0.04) = <em>population of the city in 2020</em>

(253050)(0.96) = 242928

242928 is the exact population of the city. However, it says to round to the nearest hundred. Since 28 is less than 50, then it would round down to 900.

Therefore, the answer would be 242, 900 people.

4 0
2 years ago
X/3 equals 1351 over seven
Fantom [35]
X/3=1351/7
cross multiply
7x=4053
divide by seven on both sides
x=579
5 0
3 years ago
The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by
Vikentia [17]

The answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\

suppose x = m.\frac{\pi}{6}+55 and \frac{\pi}{2} = 90 degree

We know, cos(x+90°) = - sin(X)

⇒ cos((m.\frac{\pi}{6})+55+90degree)degree = -sin((m.\frac{\pi}{6})+55)

⇒ t = sin((m.\frac{\pi}{6})+55)

Hence the answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

#SPJ4

3 0
2 years ago
-5n - 6n &lt; 8 - 8n - <br> Simplify.<br> Show work please.
Shkiper50 [21]

Answer:

-n← 2 2/3

Step-by-step explanation:

first combine like terms, and then simplify

6 0
3 years ago
Read 2 more answers
Is (a-3)(2a^2 + 3a + 3) equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)
vovikov84 [41]
<h3>Answer: Yes they are equivalent</h3>

==============================================

Work Shown:

Expand out the first expression to get

(a-3)(2a^2 + 3a + 3)

a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)

2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9

2a^3 + (3a^2-6a^2) + (3a-9a) - 9

2a^3 - 3a^2 - 6a - 9

Divide every term by 2 so we can pull out a 2 through the distributive property

2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)

This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

4 0
3 years ago
Read 2 more answers
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