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ahrayia [7]
3 years ago
8

9(a + 2b) + c for a = -3, b = -2, and c = 1.

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
6 0

Answer: -62

Step-by-step explanation:

9( a + 2b) + c

Substitute correct values for all a, b and c.

9( -3 + 2(-2) ) + 1

9( -3 - 4 ) + 1

9(-7) + 1

-63 + 1

-62.  

Ivahew [28]3 years ago
6 0

Answer:

-62

Step-by-step explanation:

replace the variables

9( -3 + 2 * -2) +1

multiply

9(-3 + -4) +1

add

9(-7) +1

multiply

-63+1

add

-62

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20
Alenkinab [10]

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{ x^2+3x-4}

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

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= \frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}

= \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= { (x-1)(x+4)}

= { x^2+3x-4}

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2 years ago
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