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Anon25 [30]
4 years ago
5

What does m equal to in 11+m=1/4m-2m?

Mathematics
2 answers:
uranmaximum [27]4 years ago
8 0
First subtract m over to 11=1/4m-2m-m then factor out an m so 11= m(1/4-2-1) so 11=m(-11/4) then divide over m=-4
a_sh-v [17]4 years ago
3 0
M in (-oo:+oo) m+11 = (1/4)*m-(2*m) // - (1/4)*m-(2*m) m-((1/4)*m)+2*m+11 = 0 m+(-1/4)*m+2*m+11 = 0 11/4*m+11 = 0 // - 11 11/4*m = -11 // : 11/4 m = -11/11/4 m = -4 m = -4
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Show that the sum of two concave functions is concave. Is the product of two concave functions also concave?
spayn [35]

Answer with explanation:

Let us assume that the 2 functions are:

1) f(x)

2) g(x)

Now by definition of concave function we have the first derivative of the function should be strictly decreasing thus for the above 2 function we conclude that

\frac{d}{dx}\cdot f(x)

Now the sum of the 2 functions is shown below

y=f(x)+g(x)

Diffrentiating both sides with respect to 'x' we get

\frac{dy}{dx}=\frac{d}{dx}\cdot f(x)+\frac{d}{dx}\cdot g(x)\\\\

Since each term in the right of the above equation is negative thus we conclude that their sum is also negative thus

\frac{dy}{dx}

Thus the sum of the 2 functions is also a concave function.

Part 2)

The product of the 2 functions is shown below

h=f(x)\cdot g(x)

Diffrentiating both sides with respect to 'x' we get

h'=\frac{d}{dx}\cdot (f(x)\cdot g(x))\\\\h'=g(x)f'(x)+f(x)g'(x)

Now we can see the sign of the terms on the right hand side depend on the signs of the function's themselves hence we remain inconclusive about the sign of the product as a whole. Thus the product can be concave or convex.

8 0
4 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
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PtichkaEL [24]

Answer:

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Step-by-step explanation:

First, we realise

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The -1.F times 9 gives us one so the days times 9 as well.

Answer = 9

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1n=n Answer:

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