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3 years ago

To prove that the subsidiary ledger agrees with the Accounts Payable controlling account balance, complete a

1 answer:

3 0

To prove that the subsidiary ledger agrees with the Accounts Payable controlling account balance, complete a B. SCHEDULE OF ACCOUNTS PAYABLE.

The Schedule of Account payable contains the listing of all vendors in the AP ledger that the company currently owes money to. It also includes the current balance of all the accounts payable to the vendors.

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Please help me

Solnce55 [7]

Answer:

4x^2-81y^2 is NOT a perfect square trinomial, factored. You know this because if you factor this to (2x+9y)(2x-9y) then you will see that the signs between terms in the parenthesis are DIFFERENT.

Step-by-step explanation:

Taking notes as you go through the course will help you retain and process the information much better than getting "help" from a site that is probably badly named.

4 0

3 years ago

Three tenths of what number is 156?

tatiyna

Answer:

520

Step-by-step explanation:

If this answer helped you then please consider marking this as brainliest and like this respone :)

7 0

2 years ago

Read 2 more answers

What property is used in the second step of solving the inequality below?

Mkey [24]

Answer: The correct option is, (B) Addition property

Step-by-step explanation:

Addition property : In this property, whatever is added to one side of the equal sign must be added to the other side.

For example : If x = y then x + z = y + z

Multiplication property : In this property, whatever is multiplied to one side of the equal sign must be multiplied to the other side.

For example : If x = y then x × z = y × z

Transitive property : If one value (x) is equal to the another value (y), which is equal to the another value (z), then the first value (x) is equal to the third value (z).

For example : If x = y and y = z then x = z

The given inequality expression is,

5x - 9 < 91

5x -9 + 9 < 91 + 9

(Using Addition property because we are adding 9 on both the side)

5x < 100

5x ÷ 5 < 100 ÷ 5

(Using Division property because we are dividing by 5 on both the side)

x < 20

Therefore, addition property is used in the second step of solving the inequality.

6 0

3 years ago

Read 2 more answers

A whole number has the first four odd prime numbers as its factors. What is the smallest value this whole number could be?

liberstina [14]

Answer:

d. 210

Step-by-step explanation:

First four distinct prime numbers = 2,3,5,7

2×3×5×7 = 210

HOPE IT HELPS!!

5 0

3 years ago

Read 2 more answers

The base of an aquarium with given volume V is made of slate and the sides are made of glass. If the slate costs seven times as

lubasha [3.4K]

Answer:

$l = \sqrt[3]{\frac{2V}{7}}$ $b = \sqrt[3]{\frac{2V}{7}}$ $h = \sqrt[3]{\frac{49V}{4}}$

Step-by-step explanation:

Represent the volume of the box with V and the dimensions with l, b and h.

The volume (V) is:

$V = l * b * h$

Make h the subject of the formula

$h = \frac{V}{lb}$

The surface area (S) of the aquarium is:

$S = lb + 2(lh + bh)$

Where lb represents the area of the base (i.e. slate):

The cost (C) of the surface area is:

$C = 7 * lb + 1 * 2(lh + bh)$

$C = 7lb + 2(lh + bh)$

$C = 7lb + 2h(l + b)$

Substitute $\frac{V}{lb}$ for h in the above equation

$C = 7lb + 2*\frac{V}{lb}(l + b)$

$C = 7lb + \frac{2V}{lb}(l + b)$

$C = 7lb + \frac{2V}{b} + \frac{2V}{l}$

Differentiate with respect to l and with respect to b

$C_l=7b - \frac{2V}{l^2}$ $=0$

$C_b=7l - \frac{2V}{b^2}$ $=0$

To solve for b and l, we equate both equations and set l to b (to minimize the cost)

$7b - \frac{2V}{l^2}=7l - \frac{2V}{b^2}$

$7l - \frac{2V}{l^2}=7b - \frac{2V}{b^2}$

By comparison:

$l =b$

$C_l=7b - \frac{2V}{l^2}$ $=0$ becomes

$7l - \frac{2V}{l^2}=0$

$7l = \frac{2V}{l^2}$

Cross Multiply

$7l^3 = 2V$

Solve for l

$l^3 = \frac{2V}{7}$

$l = \sqrt[3]{\frac{2V}{7}}$

Recall that: $l =b$

$b = \sqrt[3]{\frac{2V}{7}}$

Also recall that:

$h = \frac{V}{lb}$

$h = \frac{V}{\sqrt[3]{\frac{2V}{7}}*\sqrt[3]{\frac{2V}{7}}}$

$h = \frac{V}{\sqrt[3]{\frac{4V^2}{49}}}$

Apply law of indices

$h = \sqrt[3]{\frac{49V^3}{4V^2}}$

$h = \sqrt[3]{\frac{49V}{4}}$

The dimension that minimizes the cost of material of the aquarium is:

$l = \sqrt[3]{\frac{2V}{7}}$ $b = \sqrt[3]{\frac{2V}{7}}$ $h = \sqrt[3]{\frac{49V}{4}}$

8 0

3 years ago