Four less than the product of one and a number x

what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)

riadik2000 [5.3K]

Answer:

$y = -\frac53x + 20$

Step-by-step explanation:

Hello!

A line that is perpendicular to another has an opposite-reciprocal slope.

Meaning:

Flip the sign (+/-)
Flip the fraction

The slope perpendicular to 3/5 would be -5/3.

We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.

<h3 /><h3>Solve for B</h3>

$y = -\frac53x + b$
$-5 = -\frac53(15) + b$
$-5 = -25 + b$
$20 = b$

The y-intercept of the new line is 20.

The equation is $y = -\frac53x + 20$

6 0

2 years ago

Whoevr answers this question correctly gets brainly and show your work please

blsea [12.9K]

Answer:

1/4

Step-by-step explanation:

The chance of it landing heads up once would be 1/2

The chance of it landing heads up twice would be 1/4

The chance of it landing heads up three times would be 1/8

The chance of it landing heads up four times would be 1/16

See the pattern?

Pattern: Divide the denominator by 2.

<h2>Please give brainliest!!! :) </h2>

3 0

3 years ago

The ratio of the numerator and denominator of a rational number is 2 : 7 and

Nadya [2.5K]

Answer:

6/21.

Step-by-step explanation:

let the rational number be 2x/7x.

2x + 4 / 7x - 2 = 10 /19

Cross multiply:

19(2x + 4) = 10(7x - 2)

38x + 76 = 70x - 20

96 = 70x - 38x

32x = 96

x = 3.

So the rational number is 2*3/ 7*3

= 6/21.

4 0

3 years ago

One frame of a film in a projector is about 50 mm high. The film isOne frame of a film in a projector is about 50 mm high. The f

OlgaM077 [116]

The frame of film is actually 50 mm high, but it looks 16 m high on the screen.

Remember that 1 m = 1,000 mm.

So everything looks (16,000)/(50) = 320 times as big on the screen
as it is on the film. That's called the scale factor.

The penguin is 35 mm high on the film. He'll look 320 times bigger on the screen.

(320) x (35 mm) = 11,200 mm = 11.2 meters high

4 0

3 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago