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aniked [119]
3 years ago
11

A young equestrian loved to ride her horse all day long, dreaming of the day

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

A. Determine how far from home the daughter is when her father

leaves.

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What is the relationship between lines d and b?
docker41 [41]

Answer:

the are perpendicular to each other (option B)

5 0
2 years ago
If 62% of 80 classmates like hip-hop, but 70% of 60 relatives like hip-hop, which one is more?
SIZIF [17.4K]

62 percent of 80 is more

Step-by-step explanation:

the 62 percent of 80 comes out to 49.6 people and the other one comes out to 42 people

i dont know how to explain how to do it

8 0
2 years ago
Read 2 more answers
If Pentagon ABCDE was dilated to create Pentagon A'B'C'DE', what rule was used?
svetlana [45]

Answer:

<em>B</em> (x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)

Step-by-step explanation:

<u>Dilations</u>

Given a point A(x,y) and a scale factor k the dilated image of A, called A' is calculated as A'=(kx,ky), assuming the same scale factor is applied in both axes.

The pentagon ABCDE was dilated to create pentagon A'B'C'D'E'. To find the dilaton rule used, we must find two clear points where the coordinates of both axes can be easily read from the graph.

Point C(-2,0) maps to C'(-5,0). This gives us the scale factor for the x-axis of -5/(-2)= 5/2.

The y-coordinate of E is 2 and the y-coordinate of E' is 5. This gives us the same scale factor for the y-axis of 5/2.

Thus, the rule to dilate the pentagon is:

B \mathbf{(x,y) \rightarrow \left(\frac{5}{2}x,\frac{5}{2}y\right)}

5 0
3 years ago
Find the area of the rhombus
fenix001 [56]

Check the picture below.

since in a rhombus the diagonals bisect each other, thus EC = EA.

now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus

\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}

7 0
3 years ago
What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a
laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x

So, the mean of 11 consecutive integers is the 6th integer.

4 0
3 years ago
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