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3 years ago

11

a cell phone company charges $40 per month plus $2 for each minute of time use out of service area.Write to the equation that de

scribes the amount why that a cell phone user would pay if they use the phone for x it's out of the service area

2 answers:

aleksley [76]3 years ago

5 0

Y=40+2x is your final answer. Hope it help!

Nutka1998 [239]3 years ago

5 0

Y= 40+2x hope this helps

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Translate (11, 3) 8 units up and 14 units left<br> What’s the answer

Lubov Fominskaja [6]

Answer: 3, 11

Step-by-step explanation:

Y= 3+8 = 11

X= 11-14=3

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3 years ago

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P+3/m=-1 solve for p

e-lub [12.9K]

Look in the file below

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3 years ago

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

<h3>16</h3>

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

<h3>17</h3>

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

<h3>18</h3>

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

<h3>15</h3>

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago

The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

hoa [83]

Answer:

8 packs of bottled water and 14 packs of candy bars

Step-by-step explanation:

Provided,

Each pack of water bottles = 35 bottles

Each pack of candy = 20 candy

Since quantity of candy in each pack is small than quantity of water bottle in each pack, in order to have same quantity in numbers of both bottles and candies,

Purchase quantity of candy packs shall be more than the pack of water bottles.

Further, with this option 1 and 2 are not valid as candy packs are same or less than packs of water bottle.

In option 3 and 4, option 3 have smaller quantities as provided manager bought the least possible quantity.

Accordingly

Option 3

8 packs of water bottle = $8 \times 35 = 280 \ water\ bottles$

14 packs of candy = $14 \times 20 = 280 \ candies$

Since the quantities of water bottles and candies are same this is an opt answer.

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4 years ago

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Y = x + 7 and y = -x + 2

larisa [96]

Answer:

y = x + 7

y = (-x) + 2

X + 7 = (-x) + 2

X + X = 2 - 7

2x = (-5)

<h3>x = (-5)/2 </h3>

Putting the value of X in equation

Y = (-5/2) + 7

Y = (-5)/2 + 7/1

Equalising the denominator by Taking LCM

Y = (-5)/2 +14/2

Y = ( -5 +14)/2

<h3>Y = (9)/2 </h3>

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3 years ago