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Elina [12.6K]
3 years ago
15

How do you prepare diluted acid from concentrated acid?

Chemistry
1 answer:
lidiya [134]3 years ago
4 0
A dilute acid solution is prepared by adding the concentrated acid to water. If you do the reverse, i.e. add water to the acid it is possible that a small amount water could react with acid and boil and explode thus splashing the acid onto you or someone else near the activity. 
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Which one of the following will change the value of an equilibrium constant?
Ad libitum [116K]

Answer:

(E) changing temperature

Explanation:

Consider the following reversible balanced reaction:

aA+bB⇋cC+dD

If we know the molar concentrations of each of the reaction species, we can find the value of Kc using the relationship:

Kc = ([C]^c * [D]^d) / ([A]^a * [B]^b)

where:

[C] and [D] are the concentrations of the products in the equilibrium; [A] and [B] reagent concentrations in equilibrium; already; b; c and d are the stoichiometric coefficients of the balanced equation. Concentrations are commonly expressed in molarity, which has units of moles / 1

There are some important things to remember when calculating Kc:

-  <em>Kc is a constant for a specific reaction at a specific temperature</em>. If you change the reaction temperature, then Kc also changes

- Pure solids and liquids, including solvents, are not considered for equilibrium expression.

- The reaction must be balanced with the written coefficients as the minimum possible integer value in order to obtain the correct value of Kc

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4 years ago
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AVprozaik [17]

Answer:

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6 0
3 years ago
New evidence can lead to a change in scientific knowledge. (20 points) True False
GuDViN [60]
The answer to this question would be True.
4 0
3 years ago
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Can you help me on this?
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I can't help you with the paper because it is to small.
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3 years ago
What volume of a 0.100 M AgNO3 solution is required to completely react with the CaCl2 in 3.00 L of a 0.100 M CaCl2 solution? Th
Step2247 [10]
The balanced chemical equation for the reaction is:

2AgNO3 + CaCl2 --> 2AgCl + Ca(NO3)2

Moles of CaCl2 reacted = conc * vol = 0.100 * 3.00 = 0.300 moles

Reaction ratio between CaCl2 and AgNO3 is 1:2. Hence moles of AgNO3 = 0.300 * 2 = 0.600 moles

Volume of AgNO3 = moles / conc = 0.600 / 0.100 = 6.00L

Of course the easy shortcut is that because both solutions are the same concentration you could just multiply 3.00 * 2, however this explanation should reason it out more clearly. Hope I helped you :)
3 0
3 years ago
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