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Semmy [17]
2 years ago
10

Which mass of magnesium sulphate will be formed if 12 g of magnesium are reacted with sulphuric acid?

Chemistry
1 answer:
Alinara [238K]2 years ago
4 0

Answer:

magnesium hydrosulphate

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How sulphuric acid react with Glucose ? Give reaction​
Ierofanga [76]

Answer:

Concentrated sulfuric acid can perform a dehydration reaction with table sugar. After mixing, the color changes from white to brownish and eventually to black. The expansion of the mixture is the result of vaporization of water and CO2 inside the container.

8 0
2 years ago
Read 2 more answers
Write a balanced half-reaction for the oxidation of aqueous hydrazine N2H4 to gaseous nitrogen N2 in basic aqueous solution
Zigmanuir [339]

Answer:

N2H2(aq) + 2OH^-(aq) ----------> N2(g) + 2H2O(l) + 2e

Explanation:

Hydrazine is mostly used in thermal engineering as an anticorrosive agent. Hydrazine can be oxidized in aqueous solution as shown in the equation above. Oxidation has to do with loss of electrons and increase in oxidation number.

The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.

7 0
3 years ago
What is the charge is the ion when lithium reacts with chlorine
sladkih [1.3K]
When lithium reacts to chlorine it goes from having no charge to +1 charge, while chlorine goes from neutral to having -1 charge.
4 0
2 years ago
If you have 10,000 grams of a substance that decays with a half-life of 14 days, then how much will you have after 56 days?
Crank

Answer: 625 grams

Explanation:

14 goes into 56, 4 times.

10,000÷2=5,000 - first half life

5,000÷2=2,500 - second half life

2,500÷2=1,250 - 3rd half life

1,250÷2= 625 - 4th half life

Note: don't type "grams" after 625, just type "625".

5 0
2 years ago
A container initially holds 5.67 x 10^-2 mol of propane and has a volume of V1. The volume of the container was increased by add
Brut [27]

Answer:

Initial volume of the container (V1) = 1.27 L (Approx)

Explanation:

Given:

Number of mol (n1) = 5.67 x 10⁻²

Number of mol (n2) = (5.67 +2.95) x 10⁻² = 8.62 x 10⁻²

New volume (V2) = 1.93 L

Find:

Initial volume of the container (V1)

Computation:

Using Avogadro's law

V1 / n1 = V2 / n2

V1 / 5.67 x 10⁻² = 1.93 / 8.62 x 10⁻²

V1 = 10.9431 / 8.62

Initial volume of the container (V1) = 1.2695

Initial volume of the container (V1) = 1.27 L (Approx)

5 0
3 years ago
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