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Semmy [17]
3 years ago
10

Which mass of magnesium sulphate will be formed if 12 g of magnesium are reacted with sulphuric acid?

Chemistry
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

magnesium hydrosulphate

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This is due in five mintues please help
Fittoniya [83]

Answer:

5

Explanation:

Na, N, O, O, O

5 0
2 years ago
Answer these please ASAP need help no idea how to do these
STALIN [3.7K]

Answer:

Explanation:

Cu:

Number of moles = Mass / molar masa

2 mol = mass / 64 g/mol

Mass = 128 g

Mg:

Number of moles = Mass / molar masa

0.5 mol = mass / 24 g/mol

Mass =  g

Cl₂:

Number of moles = Mass / molar masa

Number of moles  = 35.5 g / 24 g/mol

Number of moles = 852 mol

H₂:

Number of moles = Mass / molar mass

8 mol  = Mass / 2 g/mol

Mass =  16 g

P₄:

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

O₃:

Number of moles = Mass / molar masa

Number of moles  = 1.6 g /48  g/mol

Number of moles = 0.033 mol

H₂O

Number of moles = Mass / molar masa

Number of moles  = 54 g / 18 g/mol

Number of moles = 3 mol

CO₂

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

NH₃

Number of moles = Mass / molar masa

Number of moles  = 8.5 g / 17 g/mol

Number of moles = 0.5 mol

CaCO₃

Number of moles = Mass / molar masa

Number of moles  = 100 g / 100 g/mol

Number of moles = 1 mol

a)

Given data:

Mass of iron(III)oxide needed = ?

Mass of iron produced = 100 g

Solution:

Chemical equation:

F₂O₃ + 3CO    →    2Fe  + 3CO₂

Number of moles of iron:

Number of moles = mass/ molar mass

Number of moles = 100 g/ 56 g/mol

Number of moles = 1.78 mol

Now we compare the moles of iron with iron oxide.

                        Fe          :           F₂O₃                

                           2          :             1

                          1.78       :        1/2×1.78 = 0.89 mol

Mass of  F₂O₃:

Mass = number of moles × molar mass

Mass = 0.89 mol × 159.69 g/mol

Mass = 142.124 g

100 g of iron is 1.78 moles of Fe, so 0.89 moles of F₂O₃ are needed, or 142.124 g of iron(III) oxide.

b)

Given data:

Number of moles of Al = 0.05 mol

Mass of iodine = 26 g

Limiting reactant = ?

Solution:

Chemical equation:

2Al + 3I₂   →  2AlI₃

Number of moles of iodine = 26 g/ 254 g/mol

Number of moles of iodine = 0.1 mol

Now we will compare the moles of Al and I₂ with AlI₃.

                          Al            :         AlI₃    

                          2             :           2

                         0.05         :        0.05

                           I₂            :         AlI₃

                           3            :          2

                         0.1           :           2/3×0.1 = 0.067

Number of moles of AlI₃ produced by Al are less so it will limiting reactant.

Mass of AlI₃:                            

Mass = number of moles × molar mass

Mass = 0.05 mol × 408 g/mol

Mass = 20.4 g

26 g of iodine is 0.1 moles. From the equation, this will react with 2 moles of Al. So the limiting reactant is Al.

c)

Given data:

Mass of lead = 6.21 g

Mass of lead oxide = 6.85 g

Equation of reaction = ?

Solution:

Chemical equation:

2Pb + O₂   → 2PbO

Number of moles of lead = mass / molar mass

Number of moles = 6.21 g/ 207 g/mol

Number of moles = 0.03 mol

Number of moles of lead oxide = mass / molar mass

Number of moles = 6.85 g/ 223 g/mol

Number of moles = 0.031 mol

Now we will compare the moles of oxygen with lead and lead oxide.

               Pb         :        O₂

                2          :         1

               0.03     :      1/2×0.03 = 0.015 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.015 mol × 32 g/mol

Mass =  0.48 g

The mass of oxygen that took part in equation was 0.48 g. which is 0.015 moles of oxygen. The number of moles of Pb in 6.21 g of lead is 0.03 moles. So the balance equation is

2Pb + O₂   → 2PbO

   

6 0
3 years ago
PLEASE HELP ASAP!!!!! WILL GIVE BRAINLIEST!!!!
Akimi4 [234]

Explanation:

The magnet uses electromagnetic induction meaning it can be readily magnetized and demagnetized (using electricity) when required. When electricity is switched on, it becomes magnetized and lifts an object and when electricity is switched off, it loses magnetism and releases the object.

The magnetic is able to lift heavy objects because it has powerful conductor material (ferromagnetic iron) and the number of electromagnetic coils is many to induce a powerful magnetic force. The electric current, inducing the magnetism, is also powerful.

Learn More:

For more on electromagnetic induction check out;

brainly.com/question/3414535

brainly.com/question/13369951

#LearnWithBrainly

7 0
3 years ago
If 2.00g of p-aminophenol ( 109.1 g/mol) reacts with 5.00 ml of acetic anhydride (102.1 g/mol and density = 1.08 g/ml), what mas
inna [77]
The complete reaction is as,

      4-Aminophenol + Acetic Anhydride → <span>Acetaminophen + Acetic Acid

First of all convert the ml of Acetic anhydrite to grams,
As,
                                Density  =  mass / volume
Solving for mass,
                                mass  =  Density </span>× Volume
<span>Putting values,
                                mass  =  1.08 g/ml </span>× 5ml
<span>
                                mass =  5.4 g of acetic anhydride

First Find amount of  acetic anhydride required to react completely with 2 g of p-Aminophenol,
As,
       109.1 g of p-aminophenol required  =  102.1 g of acetic anhydride
so,     2 g of p-aminophenol will require  =  X g of Acetic Anhydride

Solving for X,
                                X  =  (2 g </span>× 102.1 g) ÷ 109.1 g
 
                                X  =  1.87 g of acetic anhydride is required to be reacted.

But, we are provided with 5.4 g of Acetic Anhydride, means p-aminophenol is the limiting reactant and it controls the formation of product. Now Let's calculate for product,
As,
       109.1 g of p-aminophenol produced  =  180.2 g of <span>Acetaminophen
So    2.00 g of p-aminophenol will produce  =  X g of Acetaminophen

Solving for X,
                               X  =  (2.00 g </span>× 180.2 g) ÷ 109.1 g
 
                               X  =  3.30 g of Acetaminophen

Result:
          <span>If 2.00g of p-aminophenol reacts with 5.00 ml of acetic anhydride 3.30 g of acetaminophen is made.</span>
4 0
3 years ago
What holds matter together
Law Incorporation [45]
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