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7nadin3 [17]
3 years ago
9

One application of Hess's Law (which works for ΔH, ΔS, and ΔG) is calculating the overall energy of a reaction using standard en

ergies of formation of products and reactants. What is the standard change in free energy for the reaction: 4 KClO3(s) → 3 KClO4(s) + KCl(s)? Use the following standard gibbs energies of formation: ΔGf(KClO3(s)) = -290.9 kJ/mol; ΔGf(KClO4(s)) = -300.4 kJ/mol; ΔGf(KCl(s)) = -409 kJ/mol
Chemistry
1 answer:
VikaD [51]3 years ago
3 0

Answer:

The standard change in free energy for the reaction =  - 437.5 kj/mole

Explanation:

The standard change in free energy for the reaction:

                              4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)

Given that   ΔGf(KClO3(s)) = -290.9 kJ/mol;

                    ΔGf(KClO4(s)) = -300.4 kJ/mol;

                    ΔGf(KCl(s)) = -409 kJ/mol

According to Hess's law

ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)

               ⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}

                            = - 901.2 - 409 + 872.7

                            =  - 437.5 kj/mole

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22.5 g of silver nitrate reacts with excess magnesium bromide, determine the mass
Setler [38]

Answer:

9.82 g of Mg(NO₃)₂

Explanation:

Let's determine the reaction:

2AgNO₃  +  MgBr₂  → Mg(NO₃)₂  +  2AgBr

2 moles of nitrate silver reacts with MgBr₂ in order to produce 1 mol of magnesium nitrate and silver bromide.

We determine the moles of AgNO₃

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6 0
3 years ago
How many grams of h2 are needed to produce 14.51 g of nh3?
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Answer:

               2.57 g of H₂

Solution:

The Balance Chemical Equation is as follow,

                                          N₂  +  3 H₂    →    2 NH₃

According to Balance equation,

         34.06 g (2 moles) NH₃ is produced by  =  6.04 g (3 moles) of H₂

So,

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Solving for X,

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3 years ago
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