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3241004551 [841]
1 year ago
14

ASAP HELP

Chemistry
1 answer:
dlinn [17]1 year ago
3 0

One molecule of sucrose is burned with oxygen to make carbon dioxide and water.

Disaccharide sugar sucrose is composed of glucose and fructose. It is produced naturally by plants and is the main component of white sugar. C₁₂H₂₂O₁₁ is the chemical formula for it.

Extraction and refining sucrose for human use can be done from either sugarcane or sugar beet. Raw sugar is created from crushing the cane, which is consistently delivered to other sectors to be refined into pure sucrose. Sugar mills generally are located in the tropical regions near the sugarcane plantations.

<em>                    C₁₂H₂₂O₁₁ + 12O₂  →  12CO₂ + 11H₂O</em>

When one molecule of sucrose is burnt, we get 12 carbon dioxide molecules.

To learn more about sucrose,

brainly.com/question/978083

#SPJ1

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A sample of FeCl3 has a mass of 36.45.How many molecules would that be?
stira [4]

Answer: 1.35x 10²³ molecules FeCl3

Explanation: First find the number of moles for FeCl3 using its molar mass which is equal to 162.2 g FeCl3

Convert moles of FeCl3 to molecules by using the Avogadro's number.

8 0
3 years ago
PLEASE HELP!!!!
Vaselesa [24]

Hi!

When the ocean reaches its saturation level of carbon dioxide, a couple of things will happen:

First, more carbon dioxide will remain in the atmosphere, and second, the ocean's pH will drop.

Carbonate and bicarbonate ions in seawater act as a buffer system which keeps the ocean's pH levels stable. When CO2 dissolves in seawater, it reacts with the ocean's buffer system in such a way that it produces two hydrogen ions, which lowers the pH. As more and more CO2 reacts with the ocean's buffer system and the system becomes saturated, less atmospheric carbon dioxide will cross over into the ocean. This excess CO2 will remain in the atmosphere and contribute to global climate change.

Hope this helped!

5 0
3 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

[OH^{-}] = \frac{n_{NaOH}}{V}

Where V is the volume of the solution = 1.00 L                

[OH^{-}] = \frac{n_{NaOH}}{V} = \frac{3.01 \cdot 10^{-3} moles}{1.00 L} = 3.01 \cdot 10^{-3} mol/L

Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

pH + pOH = 14

pH = 14 - pOH = 14 - 2.52 = 11.48

Therefore, the pH of the solution is 11.48.

I hope it helps you!

3 0
3 years ago
The basic living unit of all organisms is the- A. Organ B. Tissue C. Organ System D. Cell
777dan777 [17]

Answer:

D:Cells

Explanation:

A cell is a the smallest unit of a living thing. A living thing whether made up of one cell which is Bacteria and a living thing whether made up of many cells which is Humans

5 0
3 years ago
Read 2 more answers
Phenol and benzoic acid are both weak acids that are solublein
stealth61 [152]

Answer:

Se explanation below

Explanation:

Here we will use the technique of extraction taking advantange of the different solubilities of Phenol and and Benzoic Acid in the NaOH and and NaHCO₃ solvents (In reality their anions). Notice that phenol does not dissolve in the weak base NaHCO₃ so we can have the solution of phenol and benzoic acid in ether and proceed to extract with this weak base, the phenol will remain in solution in the organic ether solution and the sodium benzoate will go into the water layer.

We then will repeat the extraction procedure to separate the phenol from the organic layer by using NaOH instead.

Benzoic Acid /

Phenol/  Ether        ⇒Extract w/     ⇒    Organic Layer = Phenol/Ether      

                                10 % NaHCO₃         Aqueous Layer = Sodium Benzoate                  

                                                             

Sodium benzoate ⇒ 10 % HCl to precipitate Benzoic Acid

Filter Precipitate  benzoic Acid ⇒ Recrystallize benzoic Acid

Phenol  / Ether                Extract w/              Organic Layer =  Eher

                                        10 % NaOH            Aqueous Layer =

                                                                       Sodium Phenolate  

 

Sodium Phenolate  ⇒ 10% HCl to precipitate Phenol                                         Filter Precipitate Phenol ⇒ Recrystallize Phenol

7 0
3 years ago
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